E4.7 Circle theorems I
- Syllabus
- 0580–2028–2029
- Topic
- E4.7
- Level
- Extended
A circle-theorem solution starts by matching an angle to an exact circle configuration, then names that theorem as the reason before moving to the next angle.
| Configuration to recognise | Angle fact | Reason to state |
|---|---|---|
| angle subtended by a diameter at the circumference | 90∘ | angle in a semicircle |
| radius and tangent at the point of contact | 90∘ | tangent is perpendicular to the radius |
| centre angle and circumference angle standing on the same arc | centre angle =2× circumference angle | angle at the centre is twice the angle at the circumference |
| two circumference angles standing on the same chord and in the same segment | equal | angles in the same segment are equal |
| four vertices on one circle | opposite angles sum to 180∘ | opposite angles of a cyclic quadrilateral are supplementary |
| tangent and chord at the contact point, compared with the angle subtended by that chord in the opposite segment | equal | alternate segment theorem |
Mark the centre, radii, diameter, tangent and the endpoints of the relevant chord. Decide which two rays form the required angle, identify the arc or chord it stands on, apply one theorem, and write its reason. Then use ordinary angle facts—triangle sum, straight line, isosceles radii or angles at a point—as separate justified steps.
Let AB be a diameter, let C lie on the circle, and let a tangent touch the circle at A. If ∠BAC=32∘, then ∠ACB=90∘ because it is an angle in a semicircle. Hence ∠ABC=180∘−90∘−32∘=58∘. The angle between the tangent at A and chord AC is also 58∘ by the alternate segment theorem.
The same chord or arc endpoints must be used when comparing centre, circumference or same-segment angles. A tangent is perpendicular only to the radius drawn to its contact point, and a quadrilateral is cyclic only when all four vertices lie on the circle. Do not choose a theorem from the picture's appearance alone.