C1.12 Rates
- Syllabus
- 0580–2028–2029
- Topic
- C1.12
- Level
- Core
A rate compares quantities with different units. The unit tells you both the division and the calculation direction: 15.20perhourmeans$15.20$ for each hour, while 20 litres per minute means 20 litres for each minute.
rate=reference quantityquantityquantity=rate×reference quantity
| Context | Read the units | Typical calculation |
|---|---|---|
| Hourly pay | dollars/hour | pay = hours × hourly rate |
| Exchange rate | new currency/old currency | old amount × rate = new amount |
| Flow rate | litres/minute | volume = flow rate × time |
| Fuel use | litres/100 km or km/litre | follow the stated unit; the two forms are not interchangeable |
At \15.20perhour,40hoursgives40\times15.20=$608.If1dollarexchangesfor1.25euros,80\times1.25=€100$; converting back divides by 1.25. Write the units beside the numbers so the unwanted unit cancels.
Convert the reference unit before applying the rate. For example, 84 km/h is 84000÷60=1400 m/min. Multiplying by 1000 changes kilometres to metres; dividing by 60 changes 'per hour' to 'per minute'.
Do not multiply automatically. Use the rate's written units to decide whether to multiply or divide, and do not assume that every fuel-consumption figure is expressed in the same direction.
Pressure, material density and population density are rates: one quantity is measured per unit of another. In this objective, the required formula is supplied in the question; your job is to match each value and unit to that formula.
| Measure | Common given formula | Meaning of the unit |
|---|---|---|
| Pressure | P=F/A | force per unit area, such as N/m² |
| Density | ρ=m/V | mass per unit volume, such as g/cm³ |
| Population density | d=N/A | people per unit area, such as people/km² |
A metal cuboid has mass 4 kg and volume 600 cm³. Convert 4 kg to 4000 g, then ρ=4000÷600=6.67 g/cm³ (3 s.f.). If density and volume are known, rearrange ρ=m/V to m=ρV.
For a population of 735 000 across 1 477 300 km², population density is 735000÷1477300≈0.498 people/km². A value below 1 is possible: it means fewer than one person per square kilometre on average, not a fraction of a person at each location.
Do not memorise extra physics formulas as syllabus requirements here. Use the formula supplied, keep numerator and denominator in the correct order, and convert mass, area or volume units before dividing.
Average speed describes a whole journey. It is the total distance travelled divided by the total elapsed time, including any stops when the question treats them as part of the journey.
average speed=total timetotal distanced=stt=sd
A cyclist travels 45 km in 3 hours 45 minutes. Since 45 minutes is 45/60=0.75 hours, the total time is 3.75 hours. The average speed is 45÷3.75=12 km/h.
For a two-stage run, first find missing totals. Running for 45 minutes at 9.5 km/h covers 9.5×0.75=7.125 km. Running 8.1 km at 7.5 km/h takes 8.1÷7.5=1.08 h. So the whole-run average is (7.125+8.1)÷(0.75+1.08)≈8.32 km/h.
To convert m/s to km/h, multiply by 60×60÷1000=3.6. To convert km/h to m/s, divide by 3.6. A decimal hour is not decimal minutes: 2.4 hours is 2 hours 24 minutes.
Do not average two speeds unless their travel times are equal. Average speed always uses total distance divided by total time; it is not generally the arithmetic mean of the stage speeds.