6. Trigonometry
- Syllabus
- 0580–2028–2029
- Section
- 6
- Level
- Core

Pythagoras' theorem connects the three side lengths of a right-angled triangle. The hypotenuse is the side opposite the right angle and is always the longest side.
c^2=a^2+b^2
Label the hypotenuse c before substituting. If c is unknown, add the two shorter-side squares and take the positive square root. If a shorter side is unknown, subtract the known shorter-side square from c2, then take the positive square root. Keep an exact surd when requested; otherwise round only the final length.
With shorter sides 7 cm and 24 cm, c=72+242=625=25 cm. If the hypotenuse is 13 cm and one shorter side is 5 cm, the other is 132−52=144=12 cm. The triples satisfy 72+242=252 and 52+122=132.
Use this theorem only when a right angle is known or can be proved. Never subtract when finding the hypotenuse. Conversely, if the square of the longest side equals the sum of the other two squares, the triangle is right-angled. Lengths use positive square roots and linear units.
Sine, cosine and tangent compare side lengths relative to one acute angle in a right-angled triangle. The hypotenuse is opposite the right angle; opposite and adjacent depend on the chosen angle.
| Ratio | Relationship | Use when the known and unknown involve |
|---|---|---|
| sine | sinheta=exthypotenuseextopposite | opposite and hypotenuse |
| cosine | cosheta=exthypotenuseextadjacent | adjacent and hypotenuse |
| tangent | anheta=extadjacentextopposite | opposite and adjacent |
Mark the right angle, circle the reference angle, then label O, A and H. Choose the ratio containing the known side and the unknown. To find a side, rearrange before evaluating. To find an angle, use the matching inverse function, such as heta=an−1(O/A). Keep the calculator in degree mode and round an angle to one decimal place unless told otherwise.
In a right triangle with hypotenuse 15 cm and angle 38∘, the opposite side is 15sin38∘=9.23… cm. If instead the opposite and adjacent sides are 5 cm and 8 cm, heta=an−1(5/8)=32.0∘ to one decimal place.
Adjacent means the non-hypotenuse side beside the chosen angle; it changes when the reference angle changes. Use inverse trig only when the angle is unknown. These ratios apply here to acute angles in right-angled triangles.
A two-dimensional trigonometry problem may hide several right triangles. Solve them in an order that turns each new length or angle into data for the next triangle.
| Information in the current right triangle | Method |
|---|---|
| two side lengths | Pythagoras' theorem |
| one acute angle and one side | sine, cosine or tangent |
| two sides and an acute angle required | inverse sine, cosine or tangent |
Sketch and label the geometry, then mark every right angle. For bearings, draw parallel north lines and measure the three-figure bearing clockwise from north; use angle facts to obtain the triangle's interior angle. Solve one right triangle at a time, carrying unrounded calculator values into later steps. State angles in degrees and give decimal angles to one decimal place.
A first right triangle has horizontal run 18 m and angle 35∘, so its rise is 18an35∘=12.603… m. That rise is perpendicular to a 24 m length in a second right triangle, giving a diagonal 242+12.603…2=27.1 m. Using the unrounded rise avoids drift.
Do not apply one ratio across sides that belong to different triangles. A bearing is referenced to north, not automatically to a horizontal edge. Keep intermediate values unrounded; round only the requested final answer. Non-right sine and cosine rules belong to Extended content.