C1.10 Limits of accuracy

Syllabus
0580–2028–2029
Topic
C1.10
Level
Core

Find the interval hidden by a rounded value

A rounded value represents an interval of possible original values. Find the rounding step, take half of it, then subtract and add that half-step to locate the lower and upper boundaries.

x- rac{r}{2}\le v<x+ rac{r}{2}

Here xx is the stated rounded value, rr is one unit at the stated accuracy, and vv is the original value. The lower bound is included; the upper bound is excluded because an exact upper-bound value rounds to the next stated value.

Stated accuracy Rounding step rr Half-step Example interval
nearest kilogram 11 kg 0.50.5 kg 428.5m<429.5428.5\le m<429.5 for 429 kg
nearest 5 g 55 g 2.52.5 g 112.5m<117.5112.5\le m<117.5 for 115 g
1 decimal place 0.10.1 unit 0.050.05 unit 76.25h<76.3576.25\le h<76.35 for 76.3 m
2 decimal places 0.010.01 unit 0.0050.005 unit 37.835h<37.84537.835\le h<37.845 for 37.84 m

Convert the stated accuracy into the variable's unit before halving. If pp is in kilograms and 12.4 kg is correct to the nearest 100 g, then r=0.1r=0.1 kg, so 12.35p<12.4512.35\le p<12.45.

For significant figures, use the place value of the final significant digit as the rounding step. For example, 350 correct to 2 significant figures has step 10, giving 345v<355345\le v<355.

Do not use the full rounding step on each side, and do not write \le at the upper bound. This Core objective asks for bounds of rounded data only; it does not require bounds for results calculated from rounded inputs.