Question 1[Maximum number: 3]Solve the following simultaneous equations.yx=32y4x5=2716\begin{aligned} \frac{y}{x} & =\frac{3}{2} \\ \frac{y^{4}}{x^{5}} & =\frac{27}{16} \end{aligned}xyx5y4=23=1627Mark as masteredShow AnswerCorrect elimination of one unknown e.g.(32)4×1x=2716 or (32x)4×1x5=2716 or y4(2y3)5=2716 or 16(8116x4)=27x5 or 16y4=27(32243y5)oe\begin{aligned} \left(\frac{3}{2}\right)^{4} \times \frac{1}{x}=\frac{27}{16} \text { or }\left(\frac{3}{2} x\right)^{4} \times \frac{1}{x^{5}}=\frac{27}{16} \text { or } \frac{y^{4}}{\left(\frac{2 y}{3}\right)^{5}}=\frac{27}{16} \text { or } 16\left(\frac{81}{16} x^{4}\right)=27 x^{5} \text { or } 16 y^{4}=27\left(\frac{32}{243} y^{5}\right) \mathrm{oe} \end{aligned}(23)4×x1=1627 or (23x)4×x51=1627 or (32y)5y4=1627 or 16(1681x4)=27x5 or 16y4=27(24332y5)oex=3 and y=92y=\frac{9}{2}y=29 oe and no other solutionsA1 for x=3 or y=92y=\frac{9}{2}y=29 oeAdd to Test