CAIE IGCSE Additional Math Algebra and Functions Questions
Use this algebra-and-functions unit hub to connect function structure, quadratics and polynomials with equations, inequalities, simultaneous systems and logarithms.
Syllabus
2028–2030
Course
Additional Mathematics 0606
Exam points
Analyse functions, quadratics and polynomial factors using domains, ranges, extrema, discriminants and theorems.
Solve modulus, quadratic, polynomial and simultaneous equations or inequalities with valid roots and intervals.
Use logarithmic and exponential graphs, laws and equations with domain checks.
The polynomial p is such that p(x)=x3+ax2+bx−2, where a and b are constants. It is given that: - x+2 is a factor of p(x) - when p(x) is divided by x-3 the remainder is 40.
Find the values of a and b.
-8+4a-2b-2=0 oe 27+9a+3b-2=40 oe Solves their linear equations in a and b to find one unknown. a=2 and b=-1 nfww A1 for a=2 or b=-1.
Question 2
[Maximum number: 5]
the equation 2x2+x−10=5.
2x2+x−10=5
leading to 2x2+x−15=0 with a valid attempt to solve to obtain 2 values for x M1 x=25,−3 A1 For both Mark final answer for this equation, A0 if - 3 is rejected x2+x−10=−5
leading to 2x2+x−5=0 M1 Must be a correct 3-term quadratic equated to zero x=4−1±41 oe 2 Dep M1 for a valid method of solution to obtain 2 values for x. Mark final answer for this equation, A0 if negative root is rejected Denominator of final answer must be positive
Question 3
[Maximum number: 4]
the axes, sketch the graph of y=5ln(4x+3). State the intercepts with the axes. State the equation of any asymptote.
B1 for correct shape in first three quadrants tending towards a vertical asymptote in the second and third quadrants. Dep B1 for curve passing through x=-0.5 oe on the x-axis, or stated and no other points on the x-axis Dep B1 for curve passing through y=5ln3 oe on the y-axis, or stated and no other points on the y-axis B1 for x=−43 oe shown on graph or stated as the equation of the asymptote. May be implied by a dotted or straight vertical line through x=−43. This is not a dependent mark.
Question 4
[Maximum number: 3]
The diagram shows the graph of y=|3x+3|. Use a graphical method to solve the inequality ∣3x+3∣⩾∣x−2∣.
Correct graph of y=|x-2| and x⩽−2.5,x⩾−0.25 B1 for correct graph of y=|x-2|. B1 for x⩽−2.5 or x⩾−0.25. B1 STRICT FT for their critical values from the two intersections of their straight-line section of graph, providing it has negative gradient.