D.2.6—Electric field strength

Syllabus
First assessment 2025
Objective
Level
HL

Calculate Electric Field Strength

Define the field

Electric field strength is force per unit positive test charge. For a point source QQ, it is directed away from positive QQ and toward negative QQ. Its SI unit is NC1\mathrm{N\,C^{-1}}.

E=\frac{F}{q}=k\frac{|Q|}{r^2}

Worked example — point-charge field

At r=1.0mr=1.0\,\mathrm{m} from Q=+2.9×108CQ=+2.9\times10^{-8}\,\mathrm{C}, E=(8.99×109)(2.9×108)/(1.0)2=2.6×102NC1E=(8.99\times10^9)(2.9\times10^{-8})/(1.0)^2=2.6\times10^2\,\mathrm{N\,C^{-1}}. Because the source is positive, the field points radially outward.

Add fields as vectors

For more than one source, calculate each electric-field vector at the point and add them. Do not add magnitudes unless all field vectors point in the same direction. The force on a particular charge is then F=qEF=qE, with its direction reversed from the field if the charge itself is negative.

Common trap

The field direction is defined using a positive test charge, not the sign of the test charge in the question. Also distinguish field strength EE from force FF: changing the test charge changes F but not the source field E.

D.2.6 Exam Analysis

Assessment in practice

1–2 marks
How it is assessed

Questions compare field strength at different distances or find the resultant field direction from two charges.

Command terms

What is / What is the direction

What earns marks

Use E=F/q or E=k|Q|/r², keep field direction defined by a positive test charge, and add multiple source fields as vectors.

Watch for

Using the sign of the test charge to define field direction, or comparing field strengths linearly rather than with inverse-square scaling.

Representative question

Question 1

[Maximum number: 1]

Two point charges, -Q and +Q, are placed as shown. Point P is at the same distance from both charges.

What is the direction of the electric field strength at P ?

Q+Q\begin{array}{cc} \circ & \circ \\ -Q & +Q \end{array}