D.2.6—Electric field strength
- Syllabus
- First assessment 2025
- Objective
- —
- Level
- HL
Define the field
Electric field strength is force per unit positive test charge. For a point source Q, it is directed away from positive Q and toward negative Q. Its SI unit is NC−1.
E=\frac{F}{q}=k\frac{|Q|}{r^2}
Worked example — point-charge field
At r=1.0m from Q=+2.9×10−8C, E=(8.99×109)(2.9×10−8)/(1.0)2=2.6×102NC−1. Because the source is positive, the field points radially outward.
Add fields as vectors
For more than one source, calculate each electric-field vector at the point and add them. Do not add magnitudes unless all field vectors point in the same direction. The force on a particular charge is then F=qE, with its direction reversed from the field if the charge itself is negative.
Common trap
The field direction is defined using a positive test charge, not the sign of the test charge in the question. Also distinguish field strength E from force F: changing the test charge changes F but not the source field E.
Questions compare field strength at different distances or find the resultant field direction from two charges.
What is / What is the direction
Use E=F/q or E=k|Q|/r², keep field direction defined by a positive test charge, and add multiple source fields as vectors.
Using the sign of the test charge to define field direction, or comparing field strengths linearly rather than with inverse-square scaling.
Representative question
Two point charges, -Q and +Q, are placed as shown. Point P is at the same distance from both charges.
What is the direction of the electric field strength at P ?
D