D.2.14 (HL)—Electric potential

Syllabus
First assessment 2025
Objective
Level
HL

Calculate Electric Potential

HL only

Use point-charge potential

Electric potential is signed and has zero at infinity. For source charge QQ, use distance rr from the charge centre. Positive QQ gives positive potential; negative QQ gives negative potential.

V_e=k\frac{Q}{r}

Worked example — negative source

For Q=1.00×108CQ=-1.00\times10^{-8}\,\mathrm{C} at r=1.00mr=1.00\,\mathrm{m}, Ve=(8.99×109)(1.00×108)/(1.00)=89.9VV_e=(8.99\times10^9)(-1.00\times10^{-8})/(1.00)=-89.9\,\mathrm{V}. At 2.00m2.00\,\mathrm{m}, it is 45.0V-45.0\,\mathrm{V}: farther away, the negative potential increases toward zero.

Combine sources

For several point charges, calculate each kQi/rikQ_i/r_i and add the scalar values. Use centre-to-point distance and convert all distances and charges before substitution. The potential does not depend on the test charge used to define it.

Check conducting spheres

Inside a charged conducting sphere in electrostatic equilibrium, the electric field is zero and the potential is constant throughout the interior. The potential need not be zero; it equals the surface potential for the ideal spherical case.

Common trap

Do not use kQ/r2kQ/r^2 for potential, and do not assume zero field means zero potential inside a conductor.

D.2.14 (HL) Exam Analysis

HL only

Assessment in practice

1–2 marks
How it is assessed

Questions calculate point-charge potential or identify potential and field inside a hollow charged conducting sphere.

Command terms

What is

What earns marks

Use Ve=kQ/r with the signed source charge and centre distance, add scalar contributions, and apply the constant-potential condition inside a charged conductor.

Watch for

Using inverse-square dependence or treating the potential inside a conductor as zero rather than constant.

Representative question

Question 1

[Maximum number: 1]

A hollow metallic sphere of radius R has a positive charge Q . P is a point a distance R2\frac{R}{2} from the centre of the sphere.

What are the electric potential and the electric field at point P ?

Electric potential

Electric field

2kQR\frac{2 k Q}{R}

4kQR2\frac{4 k Q}{R^{2}}

2kQR\frac{2 k Q}{R}

zero

kQR\frac{k Q}{R}

4kQR2\frac{4 k Q}{R^{2}}

kQR\frac{k Q}{R}

zero

Retrieve the HL D.2 Electric and Magnetic Fields Model

HL only

The HL extension is secure when you can connect electric energy, potential and field geometry.

  • Electric potential energy is assembly work from infinity
  • Ep=kq1q2/r and Ve=kQ/r are signed/scalar quantities
  • E=−ΔVe/Δr and W=qΔVe require careful sign conventions
  • Equipotentials have constant potential and zero work along them
  • Electric field lines cross equipotentials at right angles