D.4 Induction

Syllabus
First assessment 2025
Topic
Level
HL

Calculate Magnetic Flux

HL only

Define magnetic flux

Magnetic flux measures the magnetic field passing through an area. Here θ\theta is the angle between the field and the normal to the surface, not the surface itself. Flux has unit weber, Wb=Tm2\mathrm{Wb}=\mathrm{T\,m^2}.

\Phi=BA\cos\theta

Worked example — square loop

For side 6.2cm=6.2×102m6.2\,\mathrm{cm}=6.2\times10^{-2}\,\mathrm{m}, A=(6.2×102)2m2A=(6.2\times10^{-2})^2\,\mathrm{m^2}. In B=4.3×104TB=4.3\times10^{-4}\,\mathrm{T} with θ=45\theta=45^\circ, Φ=BAcosθ=1.2×106Wb\Phi=BA\cos\theta=1.2\times10^{-6}\,\mathrm{Wb}. For NN identical turns, flux linkage is NΦN\Phi.

Use flux linkage

For a coil with NN turns, the linked flux is NΦN\Phi. A change can result from changing BB, AA, θ\theta, or the number of turns. Keep the angle convention explicit: it is not generally the angle between B and the plane itself.

Check the geometry

At θ=0\theta=0, field and area normal align and Φ=BA\Phi=BA. At θ=90\theta=90^\circ, the field is parallel to the surface and Φ=0\Phi=0. Convert area to square metres before substitution.

Common trap

Do not use the angle between B and the plane when the formula expects the angle to the normal. Do not confuse flux Φ\Phi with flux linkage NΦN\Phi.

D.4.1 (HL) Exam Analysis

HL only

Assessment in practice

1 marks
How it is assessed

Questions identify flux through a coil at a stated orientation; the packet also contains one transformer item, which is adjacent but not direct evidence for flux frequency.

Command terms

State / What is

What earns marks

Use Φ=BA cosθ with θ measured from the area normal, include N only for flux linkage, and check limiting orientations.

Watch for

Using the plane angle instead of the normal angle, or adding a turn factor when the question asks for flux through one turn.

Representative question

Question 1

[Maximum number: 1]

State the magnetic flux linkage through the coil at t=0.

Apply Faraday’s Law

HL only

Use the rate of change

Faraday's law states that a changing magnetic flux linkage induces an emf. For an average emf use the finite change; for an instantaneous emf use a derivative. No change in flux linkage means no induced emf.

\varepsilon=-N\frac{\Delta\Phi}{\Delta t}\qquad\text{or}\qquad \varepsilon=-N\frac{d\Phi}{dt}

Worked example — average induced emf

For N=1200N=1200 turns, flux per turn increasing from 00 to 4.8×105Wb4.8\times10^{-5}\,\mathrm{Wb} in 2.7ms=2.7×103s2.7\,\mathrm{ms}=2.7\times10^{-3}\,\mathrm{s}, ε=NΔΦ/Δt=21V|\varepsilon|=N\Delta\Phi/\Delta t=21\,\mathrm{V}. The minus sign determines polarity through Lenz's law; it does not make the magnitude negative.

Identify what changes

Flux linkage can change because the field strength, coil area or angle changes. The minus sign gives the direction described by Lenz’s law; the magnitude is determined by how rapidly the flux changes.

Apply it to coils

An alternating current in a primary coil creates an alternating magnetic field and changing flux in a nearby secondary coil, so an emf is induced there. A steady current after switching has no changing flux and does not sustain an induced emf in the secondary.

Common trap

Do not say that a magnetic field alone induces emf. It is the change in flux linkage, not the mere presence of B, that matters.

D.4.2 (HL) Exam Analysis

HL only

Assessment in practice

1–3 marks
How it is assessed

Questions explain transformer induction or calculate an emf from a rotating/changed flux.

Command terms

Explain / What is

What earns marks

State that changing flux linkage induces emf, apply ε=−NΔΦ/Δt, and explain the sign as direction rather than an extra magnitude.

Watch for

Claiming a static field induces emf, or omitting changing flux and time rate from the explanation.

Representative question

Question 1

[Maximum number: 3]

An alternating voltage is applied to the primary coil. Explain, using Faraday's law, why a voltage is induced in the secondary coil.

Model Motional Emf

HL only

Use the motional-emf model

A straight conductor of length LL moving at speed vv perpendicular to a uniform magnetic field BB sweeps out area and develops an emf. The stated equation is restricted to the perpendicular geometry.

\varepsilon=BvL

Worked example — moving conductor

For B=120μT=120×106TB=120\,\mu\mathrm{T}=120\times10^{-6}\,\mathrm{T}, v=98.0cms1=0.980ms1v=98.0\,\mathrm{cm\,s^{-1}}=0.980\,\mathrm{m\,s^{-1}} and L=23.0cm=0.230mL=23.0\,\mathrm{cm}=0.230\,\mathrm{m}, ε=BvL=2.70×105V\varepsilon=BvL=2.70\times10^{-5}\,\mathrm{V}. Reversing either motion or field reverses polarity.

Check the motion

The conductor must cut across field lines. Motion parallel to the field produces no motional emf; increasing B, v or the length in the field increases the emf. For a complete circuit, the emf can drive current.

Explain charge separation

Moving charge carriers in the conductor experience magnetic force and separate until an internal electric force balances it. The resulting potential difference across the ends is the motional emf.

Common trap

Do not use the wire’s total length if only part is inside the field, and do not expect emf when the motion is parallel to the field lines.

D.4.3 (HL) Exam Analysis

HL only

Assessment in practice

1–3 marks
How it is assessed

Questions derive V=vBL or infer speed from voltage across a moving bar/rail system.

Command terms

Show / What is

What earns marks

Use ε=BvL for perpendicular motion, identify the active length in the field, and connect it to swept area or charge separation.

Watch for

Using a conductor length outside the field, or failing to recognize ΔA/Δt=Lv.

Representative question

Question 1

[Maximum number: 3]

Show, using Faraday's law or otherwise, that the potential difference, V, established between the ends of the rod is V=v B L.

Apply Lenz’s Law

HL only

State the direction rule

Lenz’s law says the induced emf and induced current act in a direction that opposes the change in magnetic flux that produces them. It does not oppose the magnetic field itself; it opposes the change.

Use a four-step check

  1. Identify whether external flux through the coil increases or decreases.
  2. Determine the induced field needed to oppose that change.
  3. Use the right-hand rule to find current direction/polarity.
  4. Check that the induced current would require external work, consistent with energy conservation.

Interpret emf sign

A positive or negative emf is relative to the chosen loop direction and reference terminal. The sign records polarity/direction; it is not a negative amount of energy or a separate magnitude.

Common trap

Do not make the induced field reinforce an increasing flux. That would violate energy conservation and reverse the predicted current.

D.4.4 (HL) Exam Analysis

HL only

Assessment in practice

1–2 marks
How it is assessed

Questions predict induced polarity/current or explain why a loaded secondary voltage is reduced.

Command terms

State and explain / Which law

What earns marks

Identify the flux change, choose an induced field opposing that change, then use the right-hand rule and state the polarity convention.

Watch for

Opposing the field rather than the change, or applying the right-hand rule before identifying whether flux is increasing or decreasing.

Representative question

Question 1

[Maximum number: 1]

Which law is equivalent to the law of conservation of energy?

A

Coulomb's law

B

Ohm's Law

C

Newton's first law

D

Lenz's law

Model Rotating-Coil Emf

HL only

Track one rotation

A coil rotating at constant angular speed in a uniform magnetic field has changing flux linkage. The rate of change is zero at the orientations where flux is maximum or minimum, and greatest when the flux passes through zero.

Read the emf waveform

Because the flux varies sinusoidally with rotation angle, the induced emf is sinusoidal. It changes sign every half-turn as the polarity reverses. The emf is zero when the rate of flux change is zero and has maximum magnitude when the rate is greatest.

Connect positions and graph

Match coil orientation to the graph before choosing a phase. A half-turn reverses the emf; a full turn repeats the waveform. The exact phase depends on the stated initial orientation and rotation axis.

Common trap

Do not put the emf maximum where flux is maximum. Faraday’s law depends on the rate of change of flux, not its value.

D.4.5 (HL) Exam Analysis

HL only

Assessment in practice

1–2 marks
How it is assessed

Questions match a rotation axis/orientation to an emf-time graph or identify the phase of the generated emf.

Command terms

What rotation / Draw

What earns marks

Relate coil orientation to flux and its rate of change, then identify the sinusoidal emf phase, sign reversal and period.

Watch for

Putting emf peaks at maximum flux, or changing phase without tracking the stated initial orientation.

Representative question

Question 1

[Maximum number: 1]

A rectangular coil rotates at a constant angular velocity. At the instant shown, the plane of the coil is at right angles to the line ZZZ Z^{\prime}. A uniform magnetic field acts in the direction YYY Y^{\prime}. The variation of emf with time t is shown.

What coil rotation about the axis specified produces this graph?

A

Through π2\frac{\pi}{2} about XXX X^{\prime}

B

Through π\pi about XXX X^{\prime}

C

Through π2\frac{\pi}{2} about YYY Y^{\prime}

D

Through π\pi about YYY Y^{\prime}

Relate Rotation Frequency to Emf

HL only

Read the frequency effect

For a rotating coil with fixed NN, BB and AA, increasing rotation frequency increases the rate of change of magnetic flux. The induced-emf amplitude therefore increases with frequency, while the emf waveform oscillates more rapidly.

Transform the graph

If the rotation frequency doubles, the emf period halves and the number of cycles per unit time doubles. For the same coil and field, the peak emf also doubles. If frequency is halved, period doubles and peak emf halves.

Hold variables fixed

These comparisons assume the coil area, number of turns and magnetic-field strength stay unchanged. Changing those quantities also changes the emf amplitude, so identify which parameter the question varies.

Common trap

Do not change only the period when frequency changes. For a fixed rotating coil, frequency affects both waveform frequency and peak emf through the rate of flux change.

Retrieve the D.4 Induction Model

HL only

D.4 induction is secure when you connect geometry, rate of change and direction.

  • Magnetic flux: Φ=BA cosθ
  • Changing flux linkage induces emf by Faraday’s law
  • Motional emf: ε=BvL for a perpendicular moving conductor
  • Lenz’s law gives induced direction and reflects energy conservation
  • A rotating coil produces sinusoidal emf
  • Faster rotation shortens the period and increases peak emf when other variables are fixed

Objective notes

6 learning objectives