B.5.6—Potential difference and electrical energy transfer

Syllabus
First assessment 2025
Objective
Level
HL

Calculate Electrical Energy Transfer

Energy over time

For a steady direct current,

E=Pt=IVtE=Pt=IVt

where E is electrical energy transferred in time t.

Build the relation

Potential difference is energy per charge, V=E/qV=E/q, and current is charge per time, I=q/tI=q/t. Combining them gives E=VItE=VIt.

Units and billing

Use seconds for t to obtain joules. Electricity billing may use kWh: 1kWh=3.6×106J1\,\mathrm{kWh}=3.6\times10^6\,\mathrm J.

Worked example from the mapped local textbook

A resistor carries 3A3\,\mathrm A with a potential difference of 6V6\,\mathrm V. In one second, 3C3\,\mathrm C passes and each coulomb transfers 6J6\,\mathrm J.

E=VIt=(6)(3)(1)=18JE=VIt=(6)(3)(1)=18\,\mathrm J

Therefore P=E/t=18WP=E/t=18\,\mathrm W: the resistor transfers 18J18\,\mathrm J each second.

Common trap

Do not use power in place of energy. Power is the rate of transfer; multiply by time for total energy.

B.5.6 Exam Analysis

Assessment in practice

2–3 marks
How it is assessed

The evidence asks for energy transferred over a stated duration and for the running time of a device from an energy or power budget, so unit conversion and the meaning of the time interval are central.

Command terms

Calculate

What earns marks

Use E=IVt when voltage, current and time are given. Convert the time to seconds, keep the current and potential difference in SI units, and report energy in joules. If the source or load is described, identify which component transfers the energy.

Watch for

Using hours directly in E=IVt without converting to seconds.

Representative question

Question 1

[Maximum number: 1]

Calculate the energy transferred by the lemon cell in 16 hours.