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B.5 Current and circuits

Syllabus
First assessment 2025
Topic
Level
HL

Explain How Cells Provide emf

A cell as an energy source

A cell transfers energy from a non-electrical source, such as chemical or solar energy, to charge carriers. The energy source establishes an electromotive force (emf) that can drive charge around a circuit.

Meaning of emf

The emf is the energy supplied by the source per unit charge when charge passes through the source. Its unit is the volt, 1V=1JC11\,\mathrm V=1\,\mathrm{J\,C^{-1}}.

Follow the energy

The cell is not a reservoir of charge that gets used up. Charge circulates; the cell supplies energy that is transferred in circuit components such as lamps, motors and resistors.

Common trap

Emf is not the same as current. Emf is energy per charge supplied by the source; current is charge flow per unit time.

B.5.1 Exam Analysis

Assessment in practice

1–2 marks
How it is assessed

The evidence tests short definitions and identification of emf in a circuit, including selecting the source quantity and distinguishing it from a potential difference across a component.

Command terms

State / Define / Identify

What earns marks

Define emf as energy supplied by the cell per unit charge, then distinguish it from terminal potential difference when current flows. If a numerical relationship is required, identify the charge or energy quantity first, use consistent units, and state the unit of the result.

Watch for

Treating emf as the same quantity as terminal voltage in every situation.

Representative question

Question 1

[Maximum number: 1]

State the emf of the cell.

Compare Chemical and Solar Cells

Chemical cells

A chemical cell uses chemical reactions to separate charge and provide energy per unit charge. It can provide electrical output without light, but its reactants are finite and may need replacement or recharging.

Solar cells

A photovoltaic cell converts photon energy directly into electrical energy. Its output depends on illumination and cell area; it does not generate alternating current by itself.

Compare the source, not only the circuit

Both sources provide emf and can drive a circuit. The energy-conversion mechanism, availability of input energy, output variability and storage requirements distinguish them.

Common trap

A solar cell is an energy converter, not a storage device. A secondary cell may store the electrical energy produced.

B.5.2 Exam Analysis

Assessment in practice

1–2 marks
How it is assessed

The evidence uses comparison and classification: identify a power source operating on a different principle, or recognize an incorrect statement about photovoltaic cells, especially the claim that a photovoltaic cell generates alternating current.

Command terms

Identify / Distinguish / Explain

What earns marks

Identify the source type and connect its energy conversion to the electrical output. For a solar-cell question, check whether the statement concerns photon absorption, cell area, output power, storage, or current type; do not import generator behaviour into a photovoltaic cell.

Watch for

Confusing photovoltaic cells with rotating generators and therefore claiming that their direct electrical output is alternating current.

Representative question

Question 1

[Maximum number: 1]

What is not correct about a photovoltaic cell?

A

It has an output power that is related to the surface area of the cell.

B

It generates an alternating current.

C

It absorbs energy over a range of photon frequencies.

D

It can be used to store energy in a secondary cell.

Calculate Resistance from Voltage and Current

Resistance

Resistance is the ratio of potential difference across a component to current through it:

R=VIR=\frac{V}{I}

Its SI unit is the ohm, Ω.

Interpret the ratio

For a given current, a larger potential difference means larger resistance. Resistance describes how strongly a component opposes charge flow under the stated operating conditions.

Unit check

From R=V/IR=V/I, 1Ω=1VA11\,\Omega=1\,\mathrm{V\,A^{-1}}. Use the voltage across the component, not the emf of the whole source unless they are equal in the circuit.

Common trap

Resistance is not the same as current. A component can have high resistance and a small current for a given voltage.

B.5.3 Exam Analysis

Assessment in practice

1–2 marks
How it is assessed

The evidence asks for a numerical resistance from voltage and power or tests recognition of a valid unit for resistance. Both require identifying the component quantities before calculating or selecting.

Command terms

Calculate / Identify

What earns marks

Use the resistance relationship in the form that matches the data: R=V/I, or R=V²/P when voltage and power are supplied. Show the substitution and give resistance in ohms; check that the selected voltage is the potential difference across the component.

Watch for

Using P/V or P/I as resistance without checking which power equation is being rearranged.

Representative question

Question 1

[Maximum number: 1]

What is a possible unit of electrical resistance?

A

WA2\mathrm{WA}^{-2}

B

AV1\mathrm{AV}^{-1}

C

VW2\mathrm{VW}^{-2}

D

WV2\mathrm{WV}^{-2}

Distinguish Ohmic and Non-Ohmic Behaviour

Ohm’s law

At constant temperature, an ohmic conductor has VIV\propto I, so R=V/IR=V/I is constant. Its I–V graph is a straight line through the origin when plotted with V and I consistently.

Non-ohmic behaviour

A non-ohmic component has a changing resistance, so current is not directly proportional to potential difference. Filament lamps, diodes and thermistors can be non-ohmic.

Why temperature matters

Heating can change a conductor’s resistance. Apply Ohm’s law only under the stated constant-temperature condition; otherwise the slope or ratio changes as the component operates.

Common trap

A curved I–V graph is not automatically wrong. It is evidence that the component is non-ohmic under those operating conditions.

B.5.4 Exam Analysis

Assessment in practice

1–2 marks
How it is assessed

The evidence asks learners to explain why a component is non-ohmic, so the answer must connect the graph or data to non-constant resistance or failure of direct proportionality.

Command terms

Outline / Explain

What earns marks

For an ohmic device at constant temperature, state that V is directly proportional to I and resistance is constant. For a non-ohmic graph, point to the changing gradient or changing V/I ratio rather than merely saying the graph is curved.

Watch for

Calling a component non-ohmic only because its graph is curved, without explaining that V/I or resistance changes.

Representative question

Question 1

[Maximum number: 1]

Outline why component X is considered non-ohmic.

Calculate Electrical Power

Electrical power

Power is the rate of electrical energy transfer. For a resistor,

P=IV=I2R=V2RP=IV=I^2R=\frac{V^2}{R}

Choose the convenient form

Use P=IVP=IV when current and voltage are given, P=I2RP=I^2R when current and resistance are given, and P=V2/RP=V^2/R when voltage and resistance are given.

Interpret the unit

A watt is a joule per second: 1W=1Js11\,\mathrm W=1\,\mathrm{J\,s^{-1}}. In a resistor, the transferred electrical energy becomes mainly internal energy and may produce heating.

Common trap

For alternating-current questions, distinguish peak values from mean or rms values. Use the convention and data supplied by the question.

B.5.5 Exam Analysis

Assessment in practice

1–2 marks
How it is assessed

The evidence includes a calculation from energy transferred each second and a mean-power question for an alternating supply; identify whether the stated voltage or current is peak or rms before using the equation.

Command terms

Calculate / Identify

What earns marks

Choose the power equation that matches the given quantities: P=IV, P=I²R or P=V²/R. Show the rearrangement and preserve the distinction between power, energy transferred per second, and peak or rms values in an AC question.

Watch for

Using a peak value directly in a mean-power calculation when the question requires rms quantities.

Representative question

Question 1

[Maximum number: 1]

The designers state that the energy transferred by the resistor every second is 15 J .

Calculate the current in the resistor.

Calculate Electrical Energy Transfer

Energy over time

For a steady direct current,

E=Pt=IVtE=Pt=IVt

where E is electrical energy transferred in time t.

Build the relation

Potential difference is energy per charge, V=E/qV=E/q, and current is charge per time, I=q/tI=q/t. Combining them gives E=VItE=VIt.

Units and billing

Use seconds for t to obtain joules. Electricity billing may use kWh: 1kWh=3.6×106J1\,\mathrm{kWh}=3.6\times10^6\,\mathrm J.

Common trap

Do not use power in place of energy. Power is the rate of transfer; multiply by time for total energy.

B.5.6 Exam Analysis

Assessment in practice

2–3 marks
How it is assessed

The evidence asks for energy transferred over a stated duration and for the running time of a device from an energy or power budget, so unit conversion and the meaning of the time interval are central.

Command terms

Calculate

What earns marks

Use E=IVt when voltage, current and time are given. Convert the time to seconds, keep the current and potential difference in SI units, and report energy in joules. If the source or load is described, identify which component transfers the energy.

Watch for

Using hours directly in E=IVt without converting to seconds.

Representative question

Question 1

[Maximum number: 1]

Calculate the energy transferred by the lemon cell in 16 hours.

Explain How an Electric Cell Converts Energy

Energy conversion in a cell

A chemical cell converts chemical potential energy into electrical energy. Internal chemical processes separate charge and maintain an emf between the terminals.

In a complete circuit

When the circuit is closed, charge flows and energy supplied by the cell is transferred to components. The cell’s chemical energy decreases as electrical energy is delivered.

Source versus load

The cell is the source of energy; a resistor, lamp or motor is a load where electrical energy is transferred to other forms. The charges circulate through both.

Common trap

A cell supplies energy, not a continuous supply of new electrons. The same charge carriers circulate through the circuit.

Track Conventional Current Direction

Conventional current

Conventional current is defined as the direction positive charge would move. In an external circuit it flows from the positive terminal of a source toward the negative terminal.

Do not confuse carrier motion

In a metal, mobile electrons move opposite to the conventional-current direction. Circuit arrows still follow the conventional definition unless the question explicitly asks for electron flow.

Apply it to a diagram

Trace from the positive terminal through the external components and back to the negative terminal. The current direction is consistent through a single series branch.

Common trap

The direction of conventional current is not reversed just because electrons are the actual mobile carriers in a metal.

B.5.8 Exam Analysis

Assessment in practice

1 marks
How it is assessed

The evidence asks for an arrow on a circuit diagram, so identify the relevant branch and orient the arrow using the conventional-current definition and the source polarity.

Command terms

Draw / State

What earns marks

Draw the conventional-current arrow in the direction positive charge would move through the external circuit. Follow the circuit path and use the source polarity or any stated time dependence; do not reverse the arrow merely because electrons move oppositely.

Watch for

Drawing electron-flow direction instead of conventional-current direction.

Representative question

Question 1

[Maximum number: 1]

Draw, on the circuit diagram above, an arrow showing the direction of the conventional current in the resistor for t>5.0 st>5.0 \mathrm{~s}.

Relate Current to Charge Flow

Current

Electric current is charge passing a point per unit time:

I=ΔqΔtI=\frac{\Delta q}{\Delta t}

The SI unit is the ampere, 1A=1Cs11\,\mathrm A=1\,\mathrm{C\,s^{-1}}.

Find charge or carrier count

Δq=IΔt\Delta q=I\Delta t

If each carrier has charge magnitude e, the number of carriers passing is N=Δq/eN=\Delta q/e.

Microscopic picture

Metal electrons move randomly with a small drift superimposed when current flows. Current measures net charge flow, not the total random motion of every electron.

Common trap

Use time in seconds and charge in coulombs. Do not use I/t for charge; current is already charge divided by time.

B.5.9 Exam Analysis

Assessment in practice

1–2 marks
How it is assessed

The evidence tests the conversion between current, time, charge and number of charge carriers. Identify whether the required quantity is charge or number of electrons before rearranging.

Command terms

Calculate / Identify

What earns marks

Use I=Δq/Δt to connect current with charge crossing a section per unit time. If the question asks for a number of electrons, first find the charge q=It, then divide by the elementary charge e; keep the direction or sign convention explicit.

Watch for

Using I/t for the number of electrons instead of first calculating charge q=It and then dividing by e.

Representative question

Question 1

[Maximum number: 1]

Current I flows in a conducting wire.

What expression correctly gives the number of electrons passing through a cross section of the wire in a time t ?

A

It

B

It\frac{I}{t}

C

Ite

D

Ite\frac{I t}{e}

Distinguish Direct and Alternating Current

Direct current (DC)

Direct current flows in one direction. Its charge-carrier drift direction does not periodically reverse; a cell-powered circuit is the standard example.

Alternating current (AC)

Alternating current periodically reverses direction. The potential difference and current can vary with time, so instantaneous and rms values must not be confused.

Read the syllabus boundary

The distinction is required here; detailed AC-circuit analysis is not. If an AC waveform is supplied, identify reversal, period and the value the question asks for.

Common trap

A current can have changing magnitude and still remain DC if its direction does not reverse. Direction, not constancy of size, is the defining distinction.

B.5.10 Exam Analysis

Assessment in practice

1–2 marks
How it is assessed

The evidence includes full-wave rectification and an rms-current calculation from a time graph, so classify the waveform before selecting the relevant quantity.

Command terms

Identify / Calculate / Explain

What earns marks

Identify whether the current has a constant direction or reverses periodically. In waveform questions, distinguish peak from rms values and use the stated time variation; in rectification questions, explain how the diode arrangement changes the current direction or output waveform.

Watch for

Calling a pulsating or rectified output alternating simply because its magnitude varies, without checking whether its direction reverses.

Representative question

Question 1

[Maximum number: 1]

The variation with time of the current in a resistor is shown.

What is the root mean square (rms) current?

A

0

B

1022 A\frac{10 \sqrt{2}}{2} \mathrm{~A}

C

10 A

D

102 A10 \sqrt{2} \mathrm{~A}

Apply Kirchhoff’s Circuit Laws

Junction rule

At a circuit junction, total current entering equals total current leaving:

Iin=Iout\sum I_{\mathrm{in}}=\sum I_{\mathrm{out}}

This is conservation of electric charge.

Loop rule

Around any complete circuit loop, the algebraic sum of potential changes is zero:

ΔV=0\sum\Delta V=0

This is conservation of energy.

Set signs consistently

Choose current directions and a loop direction before writing equations. A negative solved current means the actual direction is opposite to the chosen arrow.

Common trap

Kirchhoff’s laws are applications of conservation laws: the junction rule is charge conservation; the loop rule is energy conservation.

B.5.11 Exam Analysis

Assessment in practice

1–2 marks
How it is assessed

The evidence asks learners to identify the conservation laws represented by Kirchhoff’s rules or to interpret a junction relation such as I1=I2+I3.

Command terms

Identify / State

What earns marks

At a junction, set total current entering equal to total current leaving: this is charge conservation. Around a closed loop, the algebraic sum of potential differences is zero: this is energy conservation. Assign directions consistently and interpret a negative result rather than changing the law.

Watch for

Reversing the conservation principles: the junction rule is charge conservation and the loop rule is energy conservation.

Representative question

Question 1

[Maximum number: 2]

Identify the laws of conservation that are represented by Kirchhoff's circuit laws.

Relate Resistance to Resistivity and Dimensions

Resistance of a uniform conductor

R=ρLAR=\rho\frac{L}{A}

where ρ is resistivity, L is length and A is cross-sectional area. Resistivity is a material property at the stated conditions.

Read the scaling

At fixed material, doubling length doubles R. Doubling diameter makes area four times larger and reduces R to one quarter. A longer, thinner wire has greater resistance.

Units

Resistivity has SI unit Ω m. Use A=πr2A=\pi r^2 for a circular wire and convert radius/diameter to metres before calculating.

Common trap

Do not treat resistivity as the resistance of every sample of a material. Geometry changes resistance even when ρ is unchanged.

B.5.12 Exam Analysis

Assessment in practice

2–3 marks
How it is assessed

The evidence asks for a wire radius from resistance data or for the new resistance after scaling length and diameter, so proportional reasoning and cross-sectional area are central.

Command terms

Calculate / Determine

What earns marks

Use R=ρL/A and keep the geometry explicit. For a change in diameter, convert area using A∝d²; for a change in length, scale R directly with L. Give the final resistance or radius with units and explain which dimensions changed.

Watch for

Scaling diameter as though it were area, rather than using A=πd²/4 so that area scales with the square of diameter.

Representative question

Question 1

[Maximum number: 3]

The total length of the metal wire is 5.0 m . Calculate the radius of the wire.

Resistivity of the high-resistance alloy =1.5×106Ω m=1.5 \times 10^{-6} \Omega \mathrm{~m}

Analyze Series and Parallel Circuits

Series rules

In series, the same current passes through each component:

I=I1=I2I=I_1=I_2

Potential differences and resistances add: V=V1+V2V=V_1+V_2 and Rs=R1+R2R_s=R_1+R_2.

Parallel rules

In parallel, each branch has the same potential difference:

V=V1=V2V=V_1=V_2

Currents add at the junction and reciprocal resistances add:

I=I1+I2,1Rp=1R1+1R2I=I_1+I_2,\quad \frac1{R_p}=\frac1{R_1}+\frac1{R_2}

Solve systematically

Identify junctions and branches, replace simple groups with equivalent resistance, then use Ohm’s law and conservation rules to recover branch currents and voltage drops.

Common trap

Do not use the series current rule in a parallel branch or add parallel resistances directly.

B.5.13 Exam Analysis

Assessment in practice

2–3 marks
How it is assessed

The evidence includes an ideal-ammeter reading in a resistor network and a potential difference across one resistor, requiring the correct series/parallel model before substitution.

Command terms

Calculate / Determine

What earns marks

For series components, use the same current, add potential differences and resistances. For parallel branches, use the same potential difference, add branch currents, and combine reciprocals for resistance. Redraw or label the circuit before calculating a meter reading or a potential divider.

Watch for

Applying the series rule to a parallel branch, especially adding parallel resistances directly or assuming the current is the same in every branch.

Representative question

Question 1

[Maximum number: 1]

Two 1.0Ω1.0 \Omega resistors are placed in a circuit with two 6 V cells of negligible internal resistance as shown.

What is the reading on the ideal ammeter?

A

2.0 A2.0 \mathrm{~A}

B

3.0 A3.0 \mathrm{~A}

C

6.0 A6.0 \mathrm{~A}

D

12.0 A12.0 \mathrm{~A}

Model emf and Internal Resistance

Real-cell model

A real cell has emf ε and internal resistance r. With external resistance R and current I,

ε=I(R+r)\varepsilon=I(R+r)

The internal resistance accounts for energy transferred inside the cell.

Terminal potential difference

The terminal voltage across the external load is

V=IR=εIrV=IR=\varepsilon-Ir

As current increases, the internal voltage drop Ir increases and terminal voltage falls.

Use a graph

A graph of terminal V against I has intercept ε and gradient −r. A graph of ε against I with total resistance has slope R+r.

Common trap

The emf is not always the same as the terminal voltage. They are equal only when current is zero or internal resistance is negligible.

B.5.14 Exam Analysis

Assessment in practice

2–3 marks
How it is assessed

The evidence asks why terminal voltage changes when a variable resistor changes and asks for emf from a graph or equation, so separate the external load from the cell’s internal resistance.

Command terms

Explain / Determine

What earns marks

Use ε=I(R+r) when the external resistance R and current I are known. For a graph of terminal voltage V against current I, use the intercept for ε and the negative gradient for r. Explain that changing the external resistance changes current and therefore the internal voltage drop Ir.

Watch for

Reading the terminal-voltage intercept as zero or treating the gradient of a V–I graph as positive internal resistance.

Representative question

Question 1

[Maximum number: 2]

Determine the emf of the cell.

Analyze Variable Resistance

Variable resistance

A variable resistor lets the resistance in a circuit be changed. Increasing the resistance of a series variable resistor reduces the current for a fixed supply voltage. A rheostat normally uses two terminals to control current; a potentiometer uses three terminals as a potential divider.

Predict the circuit response

For a fixed supply, use I=V/RtotalI=V/R_{total}. If the variable resistance increases, total resistance increases and current decreases. In a series circuit, the potential difference across the variable resistor increases while the potential difference across a fixed series component decreases.

Sensor examples

An LDR has resistance that depends on incident light intensity. An NTC thermistor has lower resistance at higher temperature. These components allow a circuit to respond to its surroundings, but the resistance–stimulus relationship must be obtained from data or a stated model.

Common trap

Do not assume that “more resistance” means a larger current. First decide whether the supply voltage is fixed and whether the component is in series or parallel. For an internal-resistance investigation, changing a variable resistor is useful because it creates multiple VV-II data points.

B.5.15 Exam Analysis

Assessment in practice

1–2 marks
How it is assessed

The evidence asks how a variable resistance improves an internal-resistance investigation and asks for the temperature range in which a thermistor is most sensitive, linking circuit control to interpretation of component data.

Command terms

Outline / State

What earns marks

Explain how changing the variable resistance changes total resistance, current and the potential differences in a series circuit. For thermistors, read the sensitivity range from the stated resistance–temperature data or graph; do not assume a universal temperature range.

Watch for

Claiming that increasing a series variable resistance increases current, or giving a thermistor sensitivity range without reading the data provided.

Representative question

Question 1

[Maximum number: 2]

Outline how using a variable resistance could improve the accuracy of the value found for the internal resistance. provided.

Retrieve the B.5 Current and Circuits Model

Source and transfer

Cells provide emf arepsilonarepsilon, the energy transferred per unit charge by the source. Electrical energy transferred in a circuit is E=VItE=VIt, and power is P=VI=I2R=V2/RP=VI=I^2R=V^2/R. Keep emf, terminal potential difference, energy and power distinct.

Current and circuit laws

Conventional current is the direction positive charge would move, with I=Δq/ΔtI=\Delta q/\Delta t. In DC, the direction is constant; in AC, it reverses periodically. Apply Kirchhoff’s junction rule to charge conservation and the loop rule to energy conservation.

Resistance model

Use R=V/IR=V/I for a component, R=hoL/AR= ho L/A for a uniform conductor, and the correct series or parallel combination rule. Ohmic behaviour means constant resistance at constant physical conditions; non-ohmic behaviour requires reading the gradient or ratio from the graph at the stated point.

Real and variable components

For a real cell, arepsilon=I(R+r)arepsilon=I(R+r) and V= arepsilon-Ir. A variable resistor changes circuit resistance; LDRs and thermistors use a stimulus-dependent resistance. Before calculating, draw or inspect the circuit, identify the fixed quantity, and state the relevant assumption.

Explore Ohm's Law by Changing Voltage and Resistance

ConceptIB Physics HL