B.3 Gas laws
- Syllabus
- First assessment 2025
- Topic
- —
- Level
- HL
Pressure
Pressure is perpendicular force distributed over area:
P=AF⊥
Its SI unit is the pascal, 1Pa=1Nm−2.
Use the normal component
Only the component of force perpendicular to the surface contributes to pressure on that surface. A tangential component produces shear rather than normal pressure.
Read the proportionality
At fixed force, doubling area halves pressure. At fixed area, doubling the perpendicular force doubles pressure. Pressure is a scalar even though the force producing it has direction.
Common trap
Do not use total force if the force is angled. Resolve it perpendicular to the surface first, and keep area in square metres.
The evidence includes a units-concept multiple choice and a structured force/area calculation with an angled force.
State / Estimate / Determine
Use pressure as perpendicular force per unit area: P=F⊥/A. Resolve any angled force before calculating, use area in m², and state Pa or N m⁻². For energy-density questions, recognize that pressure has the same units as energy per volume.
Using total angled force rather than its perpendicular component or reporting force units instead of pascals.
Representative question
Estimate the maximum safe mass that this arrangement can hold.
F=4PA=4(1.6×105)(15×24×1.8)=4.14×108 NF=mgcosθ=m(9.8)(cos4)=9.78 m Nm=gcosθ4PA=9.784.14×108=4.3×107 kg
Do not award MP2 if the cos θterm is omitted.
Allow ECF for MP3.
Amount of substance
The amount of substance n counts how many groups of NA particles are present:
n=NAN
where N is the number of particles and NA is the Avogadro constant.
Connect mass to moles
If molar mass is M, then
n=Mm
Use matching units for m and M. Once n is known, the number of particles is N=nNA.
Use ratios efficiently
For equal numbers of particles, the samples contain equal amounts in moles even if their masses differ. For isotope or element comparisons, calculate moles before comparing particle counts.
Common trap
Do not confuse N (number of particles) with NA (particles per mole) or n (amount in moles).
The evidence uses particle-number ratios for different isotopes and a calculation of the mass of one copper atom from molar mass and Avogadro’s constant.
Calculate / Determine
Use n=N/N_A for particle counts and n=m/M for mass-to-moles conversions. Compare moles before comparing numbers of atoms or molecules, and keep mass units consistent with molar mass.
Comparing sample masses directly without accounting for molar mass, or confusing N with n.
Representative question
What is the number of atoms in 40 g of Krypton- 80 number of atoms in 20 g of Neon- 20 ?
41
21
2
4
C
Ideal-gas model
An ideal gas is a kinetic-theory model: particles are in constant random motion, occupy negligible volume compared with the container, and interact negligibly except during collisions. Collisions are treated as elastic.
Connect microscopic and macroscopic quantities
Temperature is related to average translational kinetic energy. Pressure comes from momentum transfer when particles collide with the container walls. More energetic or more frequent collisions can increase pressure.
It is an approximation
Real gases have finite-size particles and intermolecular forces. The ideal model is most reliable when particles are far apart and interactions are relatively unimportant.
Common trap
The model does not say every particle has the same speed. It uses a distribution of speeds and averages over many particles.
The evidence uses a two-mark outline of the kinetic theory and a multiple-choice question about elastic collisions with container walls.
Outline / State
Describe the kinetic-theory assumptions that connect observables to molecules: random motion, elastic wall collisions, momentum transfer causing pressure, and temperature related to average kinetic energy.
Saying all particles have the same speed or that pressure is a static property unrelated to collisions.
Representative question
Outline how the kinetic theory of gases relates observable properties of a gas to the motion of the molecules.
«absolute» temperature is proportional to/related to the KE of the molecules. pressure is related to the «average» rate of momentum transfer due to the collisions of the molecules with the container
OR
average force molecules exert per unit area.
OR pressure is the result of molecular force on/collisions with the container walls.
Higher pressure is the result of higher KE of molecules « in constant random motion » or vice versa
OK to use atoms/molecules/particles
2 max
One relation for a fixed amount of gas
The constant-pressure, constant-volume and constant-temperature observations combine to give
TPV=constant
provided the amount of gas is unchanged.
Compare two states
T1P1V1=T2P2V2
Temperatures must be absolute. If pressure and temperature stay fixed, volume is fixed; if volume and temperature stay fixed, pressure is fixed.
Use the constraint first
Name what is constant before choosing a simplified law: Boyle-type behaviour uses constant T, Charles-type behaviour uses constant P, and pressure–temperature behaviour uses constant V.
Common trap
Do not apply PV/T=constant after gas has been added or removed unless the problem explicitly tracks the changed amount of gas.
The evidence tests pressure after joining containers at constant temperature and a temperature calculation for an isobaric process.
Determine / Show
For fixed amount of gas use P₁V₁/T₁=P₂V₂/T₂. Identify the constant process before simplifying; use kelvin and preserve units. For connected containers at the same temperature, conserve total PV and divide by total volume.
Changing the gas amount without accounting for it, or using Celsius in the combined gas law.
Representative question
Two containers of volume 0.20 m3 and 0.10 m3 are filled with an ideal gas. The pressure in the larger container is 3.0×104 Pa. The pressure in the smaller container is 9.0×104 Pa. The temperature of the gas in both containers is the same. A thin tube with a valve joins the containers. The valve is initially closed.
The valve is opened so that gas can move from one container to the other. The temperature remains unchanged.
Determine the new pressure of the gas.
ALTERNATIVE 1
pressure due to gas in left container 3.0×104×0.300.20=2.0×104 «Pa» pressure due to gas in right container 9.0×104×0.300.10=3.0×104 «Ра» adding gives P=5.0×104 «Ра»
ALTERNATIVE 2
number of moles <<in a container is>> RT3.0×104×0.20ORRT9.0×104×0.10
P×0.30=(RT3.0×104×0.20+RT9.0×104×0.10)RT
P=5.0×104≪ Pa≫
ALTERNATIVE 3
Use of P1V1+P2V2=P(V1+V2)
3.0×104×0.2+9.0×104×0.1=P(0.2+0.1)
P=5.0×104≪Pa≫
Molar form
For an ideal gas,
PV=nRT
Use n in mol, T in kelvin and R=8.31JK−1mol−1.
Particle form
Using the number of particles N, the same law is
PV=NkBT
where kB is the Boltzmann constant. The forms are equivalent because R=NAkB and N=nNA.
Choose the form from the data
Use the molar form when amount of substance is given. Use the particle form when a question asks for the number of molecules or gives microscopic quantities. Rearrange before substituting, for example N=PV/(kBT).
Common trap
Do not use Celsius in either equation, and do not mix n with N. Pressure must be in pascals and volume in cubic metres for SI results.
The evidence includes finding the number of molecules from a graph-derived PV product and determining a constant from PV data.
Determine
Choose PV=nRT for moles and PV=NkBT for molecules. Rearrange clearly, use kelvin, pascals and cubic metres, and state the required number of particles or amount.
Using R with N or kB with n, or failing to convert temperature and volume to SI units.
Representative question
The laboratory is at a constant temperature of 291 K .
Determine the number of molecules in the fixed mass of gas.
« N=kBTK=1.38×10−23×2911.59 so»
N=3.96×1020
Allow use of N=kBTPV, where P
and V are taken from graph.
Pressure from collisions
Gas particles collide with a wall and change momentum. The wall exerts a force on the particles; by Newton’s third law, the particles exert an equal and opposite force on the wall. Pressure is this normal force per unit area.
Kinetic-theory relation
For an ideal gas,
P=31ρv2
where ρ is gas density and v2 is the mean square molecular speed. The speed in this equation is not simply the square of the average speed.
Read the trends
Greater molecular speed increases momentum change per collision and collision rate, increasing pressure. At fixed speed, greater density means more mass per unit volume and therefore greater pressure.
Common trap
A single particle’s collision force is not the total gas force. Pressure is a statistical average over many collisions on the surface.
The evidence asks for a Newton’s-third-law explanation of gas pressure and a qualitative piston/collision-force comparison at constant temperature.
Outline / Determine
Explain pressure through momentum change in particle–wall collisions and Newton’s third law. For calculations use P=⅓ρv̄², distinguish mean square speed from mean speed, and keep density in kg m⁻³.
Using pressure as a force without area, or confusing average molecular force with total force.
Representative question
Outline, by reference to Newton's third law, how a gas in a container exerts pressure on the container walls.
momentum of molecules/particles changes at each collision with container/walls
so container/walls exert forces on molecules/particles
<<by N3>> molecules/particles exert a force on container/walls
Marking guidance:
Award [1 max] for using 'gas' instead of 'molecules/particles'.
Max 2
Internal energy model
For an ideal monatomic gas, internal energy is the total random translational kinetic energy of its particles:
U=23NkBT=23nRT
What is included
The model includes translational kinetic energy only. It neglects intermolecular potential energy and does not include rotational or vibrational molecular energy.
Read the dependence
At fixed amount of gas, U is proportional to T. At fixed temperature, U is proportional to N or n. Particle mass does not appear directly in U=23NkBT.
Common trap
Equal mass samples of different monatomic gases do not necessarily have equal internal energy: compare their number of particles or moles at the same temperature.
The evidence compares internal energies of equal-mass helium and neon at the same temperature and asks for moles from a U–T graph.
Determine / Calculate
Use U=3/2NkBT=3/2nRT for a monatomic ideal gas. At equal temperature compare N or n, not sample mass alone; for a graph of U versus T use the gradient 3nR/2.
Assuming equal mass means equal internal energy or using a molecular-gas formula with rotational/vibrational terms not in the monatomic model.
Representative question
Two containers are filled with monatomic gas of equal mass at the same temperature. One container holds helium and the other neon.
The mass of a neon atom is five times the mass of a helium atom.
What is internal energy of the neon gas internal energy of the helium gas ?
51
1
5
5
D
Good approximation
A real gas is closest to the ideal-gas model at relatively low pressure and low density, where particles are far apart and intermolecular forces and particle volume are small compared with the container volume.
Temperature matters
Higher temperature gives particles more kinetic energy, making attractive interactions less important. Low temperature increases the importance of intermolecular attractions and can bring the gas closer to condensation.
Where it fails
At high pressure or high density, particles are crowded: their finite size and interactions matter. Near phase changes, the ideal model is especially unreliable.
Use the full condition
Do not state only “high temperature”. The reliable region is generally high temperature together with low pressure or low density.
The evidence asks why an ideal-gas pressure prediction becomes unreliable at very small volume/high pressure and asks for the pressure/density conditions where the model is valid.
State / Suggest
State that the ideal approximation is better at low pressure and low density, and generally higher temperature. At very small volumes or high pressures, particle volume and intermolecular forces violate model assumptions.
Saying only high temperature without low pressure/low density, or claiming the model improves at high pressure.
Representative question
Under which conditions of pressure and density will a real gas approximate to an ideal gas?
Pressure
Density
high
high
high
low
low
high
low
low
D
Macroscopic equations
Pressure is P=F⊥/A. For a fixed amount of gas, empirical laws combine to PV/T=constant, and the ideal-gas equations are PV=nRT=NkBT.
Microscopic model
Particles move randomly and collide elastically with walls. Momentum transfer produces pressure, with P=31ρv2. For a monatomic ideal gas, U=23NkBT=23nRT.
Bridge the descriptions
Use n=N/NA to move between moles and particles. Choose the equation from the data provided, convert temperature to kelvin, and keep SI units consistent.
Model boundary
The ideal approximation works best at high temperature and low pressure or density. At high density, high pressure or near condensation, finite particle size and intermolecular forces matter.