B.5.12—Resistance and resistivity

Syllabus
First assessment 2025
Objective
Level
HL

Relate Resistance to Resistivity and Dimensions

Resistance of a uniform conductor

R=ρLAR=\rho\frac{L}{A}

where ρ is resistivity, L is length and A is cross-sectional area. Resistivity is a material property at the stated conditions.

Read the scaling

At fixed material, doubling length doubles R. Doubling diameter makes area four times larger and reduces R to one quarter. A longer, thinner wire has greater resistance.

Units

Resistivity has SI unit Ω m. Use A=πr2A=\pi r^2 for a circular wire and convert radius/diameter to metres before calculating.

Worked example from the mapped local textbook

Nichrome has ρ=1.1×106Ωm\rho=1.1\times10^{-6}\,\Omega\,\mathrm m. A wire has L=1.96mL=1.96\,\mathrm m and radius r=0.21mm=0.21×103mr=0.21\,\mathrm{mm}=0.21\times10^{-3}\,\mathrm m.

A=πr2=1.39×107m2A=\pi r^2=1.39\times10^{-7}\,\mathrm{m^2}

R=ρLA=(1.1×106)(1.96)1.39×107=16ΩR=\frac{\rho L}{A}=\frac{(1.1\times10^{-6})(1.96)}{1.39\times10^{-7}}=16\,\Omega

Converting the radius before squaring prevents a factor-of-10610^6 error.

Common trap

Do not treat resistivity as the resistance of every sample of a material. Geometry changes resistance even when ρ is unchanged.

B.5.12 Exam Analysis

Assessment in practice

2–3 marks
How it is assessed

The evidence asks for a wire radius from resistance data or for the new resistance after scaling length and diameter, so proportional reasoning and cross-sectional area are central.

Command terms

Calculate / Determine

What earns marks

Use R=ρL/A and keep the geometry explicit. For a change in diameter, convert area using A∝d²; for a change in length, scale R directly with L. Give the final resistance or radius with units and explain which dimensions changed.

Watch for

Scaling diameter as though it were area, rather than using A=πd²/4 so that area scales with the square of diameter.

Representative question

Question 1

[Maximum number: 3]

The total length of the metal wire is 5.0 m . Calculate the radius of the wire.

Resistivity of the high-resistance alloy =1.5×106Ω m=1.5 \times 10^{-6} \Omega \mathrm{~m}