A.5.11 (HL)—Length contraction
- Syllabus
- First assessment 2025
- Objective
- —
- Level
- HL
Use the contraction equation
If L0 is the proper length measured in the object’s rest frame, an observer who sees the object moving at speed v measures L=L0/γ, with γ=1/1−v2/c2.
Select the proper length
Find the frame in which the object is at rest; that frame measures L0. Calculate γ, then divide the proper length by γ. The endpoints must be measured simultaneously in the observer’s frame.
Check the result
Since γ≥1, a moving observer measures L≤L0. At low speed the contraction is negligible; as v approaches c, the measured length along the direction of motion becomes substantially smaller.
Worked example from local Question Bank row 30450
A rocket's proper length is L0=450m and γ=5/3. An observer who sees it moving measures
L=γL0=5/3450=270m
Only the dimension parallel to the relative motion is contracted.
Common trap
Do not contract a length perpendicular to the motion, and do not multiply by γ when the requested quantity is the moving-frame length.
Questions ask you to calculate a moving space station’s length or compare a spaceship measurement with an Earth-frame distance. The evidence rewards finding γ and applying the division in the correct direction.
Calculate
Identify L0 as the object’s rest-frame length, calculate γ = 1/√(1 − v²/c²), and use L = L0/γ for the moving observer. State that the measurement is along the direction of motion and check that L is no greater than L0.
Multiplying the proper length by γ or applying contraction to a direction perpendicular to the relative motion.
Representative question
Calculate the length of the space station according to observer B, with reference to special relativity.
γ= « {1−120.621}>=1.25
«100/1.25 =>80«m»