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IB Chemistry SL 3.1 Proton Transfer Reactions Question Bank

Practise IB Chemistry SL 3.1 with questions on Brønsted–Lowry acids and bases, pH, neutralization, indicators and titration curves.

Syllabus
First assessment 2025
Course
Chemistry SL
Level
SL

3.1 Proton transfer reactions question 1

[Maximum number: 1]

Two hydrides of nitrogen are ammonia and hydrazine, N2H4\mathrm{N}_{2} \mathrm{H}_{4}. One derivative of ammonia is methanamine whose molecular structure is shown below.

Figure for Question 3.1 Proton transfer reactions question 1 — IB Chemistry SL

Hydrazine reacts with water in a similar way to ammonia. Deduce an equation for the reaction of hydrazine with water.

3.1 Proton transfer reactions question 2

[Maximum number: 3]

Chlorine undergoes many reactions.

Question (a)

(a)

Chlorine gas reacts with water to produce hypochlorous acid and hydrochloric acid.

Cl2( g)+H2O(l)HClO(aq)+HCl(aq)\mathrm{Cl}_{2}(\mathrm{~g})+\mathrm{H}_{2} \mathrm{O}(\mathrm{l}) \rightleftharpoons \mathrm{HClO}(\mathrm{aq})+\mathrm{HCl}(\mathrm{aq})
[ 3 ]

Question (i)

(i)

Hypochlorous acid is considered a weak acid. Outline what is meant by the term weak acid.

[ 1 ]

Question (ii)

(ii)

State the formula of the conjugate base of hypochlorous acid.

[ 1 ]

Question (iii)

(iii)

Calculate the concentration of H+(aq)\mathrm{H}^{+}(\mathrm{aq}) in a HClO(aq) solution with a pH=3.61.

[ 1 ]

3.1 Proton transfer reactions question 3

[Maximum number: 3]

Soluble acids and bases ionize in water.

Question (a)

(a)

Sodium hypochlorite ionizes in water.

OCl(aq)+H2O(l)OH(aq)+HOCl(aq)\mathrm{OCl}^{-}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(\mathrm{l}) \rightleftharpoons \mathrm{OH}^{-}(\mathrm{aq})+\mathrm{HOCl}(\mathrm{aq})
[ 2 ]

Question (i)

(i)

Identify the amphiprotic species.

[ 1 ]

Question (ii)

(ii)

Identify one conjugate acid-base pair in the reaction.

Table for Question (ii) — IB Chemistry SL
[ 1 ]

Question (b)

(b)

A solution containing 0.510 g of an unknown monoprotic acid, HA , was titrated with 0.100 moldm3NaOH(aq).25.0 cm30.100 \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{NaOH}(\mathrm{aq}) .25 .0 \mathrm{~cm}^{3} was required to reach the equivalence point.

[ 1 ]

Question (i)

(i)

Calculate [H+]\left[\mathrm{H}^{+}\right]in the NaOH solution.

[ 1 ]
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