CourseCourseConceptConceptDocsDocuments

IB Chemistry SL Structure 3 Classification of Matter Questions

Practise IB Chemistry SL Structure 3 with reviewed questions on periodicity, functional groups, organic formulas, physical trends, spectroscopy and matter.

Syllabus
First assessment 2025
Course
Chemistry SL
Level
SL

Exam points

  • Use periodic position and electron configuration to classify elements and predict chemical behaviour.
  • Explain periodic trends, group reactivity, oxide character and oxidation states using chemical evidence.
  • Deduce organic structures, formulae and IUPAC names from connectivity and reaction evidence.
  • Identify functional groups and homologous series, and relate isomerism and intermolecular forces to physical properties.
  • Use mass spectrometry, infrared and proton NMR evidence to identify an organic structure.

Covered syllabus points

3.1 The periodic table3.2 Functional groups: Organic compounds

Learn this topic

Study Structure 3. Classification of matter conceptsOpen the corresponding Concept lesson for explanations, examples and exam connections.

Question 1

[Maximum number: 1]

Lithium and boron are elements in period 2 of the periodic table. Lithium occurs in group 1 (the alkali metals) and boron occurs in group 3. Isotopes exist for both elements.

Distinguish between the terms group and period.

Question 2

[Maximum number: 3]

Strychnine, C21H22 N2O2(Mr=334.4)\mathrm{C}_{21} \mathrm{H}_{22} \mathrm{~N}_{2} \mathrm{O}_{2}\left(M_{\mathrm{r}}=334.4\right), is a white crystalline solid obtained from plants.

Question (a)

(a)

The formula of strychnine is:

Figure for Question (a) — IB Chemistry SL
[ 3 ]

Question (i)

(i)

State the type of structural formula shown.

[ 1 ]

Question (ii)

(ii)

State the name of the functional group containing the nitrogen atom labelled "1".

[ 1 ]

Question (iii)

(iii)

State the number of rings in strychnine's structure.

[ 1 ]

Question 3

[Maximum number: 5]

Iron rusts in the presence of oxygen and water. Rusting is a redox process involving several steps that produces hydrated iron(III) oxide, Fe2O3∙nH2O\mathrm{Fe}_{2} \mathrm{O}_{3} \bullet \mathrm{nH}_{2} \mathrm{O}, as the final product. The half-equations involved for the first step of rusting are given below.

Half-equation 1: Fe(s)→Fe2+(aq)+2e−\quad \mathrm{Fe}(\mathrm{s}) \rightarrow \mathrm{Fe}^{2+}(\mathrm{aq})+2 \mathrm{e}^{-}

Half-equation 2: O2(aq)+4e−+2H2O(l)→4OH−(aq)\quad \mathrm{O}_{2}(\mathrm{aq})+4 \mathrm{e}^{-}+2 \mathrm{H}_{2} \mathrm{O}(\mathrm{l}) \rightarrow 4 \mathrm{OH}^{-}(\mathrm{aq})

Question (a)

(a)

Identify the oxidation number of each atom in the three species in half-equation 2.

Figure for Question (a) — IB Chemistry SL
[ 2 ]

Question (b)

(b)

State the property that determines the order in which elements are arranged in the periodic table.

[ 1 ]

Question (c)

(c)

State the relationship between the electron arrangement of an element and its group and period in the periodic table.

[ 2 ]
All question bank results loaded