IB Chemistry SL 1.5 Chemical Quantities Question Bank
Practise IB Chemistry SL 1.5 with evidence-led questions on moles, equations, chemical quantities and quantitative data.
- Syllabus
- First assessment 2025
- Course
- Chemistry SL
- Level
- SL
Practise IB Chemistry SL 1.5 with evidence-led questions on moles, equations, chemical quantities and quantitative data.
Iron may be extracted from iron (II) sulfide, FeS.
The first step in the extraction of iron from iron (II) sulfide is to roast it in air to form iron (III) oxide and sulfur dioxide.
Write the equation for this reaction.
4FeS(s)+7O2( g)→2Fe2O3( s)+4SO2( g)
Marking guidance:
Accept any correct ratio.
Iron rusts in the presence of oxygen and water. Rusting is a redox process involving several steps that produces hydrated iron(III) oxide, Fe2O3∙nH2O, as the final product. The half-equations involved for the first step of rusting are given below.
Half-equation 1: Fe(s)→Fe2+(aq)+2e−
Half-equation 2: O2(aq)+4e−+2H2O(l)→4OH−(aq)
Hydrogen peroxide decomposes according to the equation below.
The rate of the decomposition can be monitored by measuring the volume of oxygen gas released. The graph shows the results obtained when a solution of hydrogen peroxide decomposed in the presence of a CuO catalyst.

The experiment is repeated with the same amount of a more effective catalyst, MnO2, under the same conditions and using the same concentration and volume of hydrogen peroxide. On the graph above, sketch the curve you would expect.
steeper curve with a similar shape that reaches same maximum volume of O2;
Outline how the initial rate of reaction can be found from the graph.
(draw a) tangent to the curve at origin/time =0 / start of reaction; (calculate) the gradient/slope (of the tangent);
Outline a different experimental procedure that can be used to monitor the decomposition rate of hydrogen peroxide.
measure/monitor mass/pressure/ [H2O2];
Marking guidance:
Accept measure/monitor temperature of system.
A Maxwell-Boltzmann energy distribution curve is drawn below. Label both axes and explain, by annotating the graph, how catalysts increase the rate of reaction.


y-axis: probability / fraction of molecules/particles / probability density Allow "number of particles/molecules" on y-axis.
and
x-axis: (kinetic) energy;
Accept "speed/velocity" on x-axis.
correct relative position of Ea catalysed and Ea uncatalysed;
more/greater proportion of molecules/collisions have the lower/required/catalysed Ea (and can react upon collision);
M3 can be scored by shading and annotating the graph.
Accept a greater number/proportion of successful collisions as catalyst reduces Ea.
Describe two characteristics of a reaction at equilibrium.
Any two:
- Rate of forward reaction equals rate of backward/reverse reaction.
- Concentrations of reactants and products remain constant.
- No change in macroscopic properties.
- Closed/isolated system or constant matter/energy.
Describe how a catalyst increases the rate of a reaction.
Provides an alternative pathway of lower energy.
Lowers activation energy of the reaction / more particles have E≥Ea.
State and explain the effect of a catalyst on the position of equilibrium.
No effect on the position of equilibrium.
It increases the rate of forward and reverse reactions equally.
Ethanoic acid reacts with ethanol to form the ester ethyl ethanoate.
The esterification reaction is exothermic. State the effect of increasing temperature on the value of the equilibrium constant ( Kc ) for this reaction.
decreases
The reaction between ethanoic acid and ethanol is homogeneous and reversible.
Deduce the expression for the equilibrium constant, K, for this reaction.
⟨K=⟩[C2H6O][C2H4O2][C4H8O2][H2O]
Marking guidance:
Do not accept expression without
H2O.
0.6 moles each of ethanol and ethanoic acid at 60∘C reacted in the presence of an acid catalyst. The volume remained constant. At equilibrium 0.2 moles of ethanoic acid remained in the reaction mixture.
Calculate the amounts, in mol, of ethanol, ethyl ethanoate and water at equilibrium.
«amount of» ethanol =0.2 «mol»
«amount of» ethyl ethanoate =0.4 «mol»
AND
«amount of» water =0.4 «mol»
Explain the effect of reducing the temperature on the value of the equilibrium constant.
value would be higher
AND
reaction is exothermic in the forward direction/equilibrium will shift to the right
Sketch the Maxwell-Boltzmann energy distribution curve for this reaction. Label the activation energy with and without a catalyst on the diagram.

Fraction of particles
Ea with catalyst Kinetic energy
correct shape curve starting at the origin, without touching the x axis at high energy.
( Ea ) catalysed <(Ea) uncatalysed on x axis.