Edexcel IAL Chemistry 18.5 benzene electrophilic substitution mechanismsShow the full mechanism: generate the electrophile, draw attack from the benzene π system, form the arenium ion and regenerate aromaticity and catalyst.SyllabusFirst assessment 2019CourseChemistry YCH11LevelA2
Exam pointsWrite equations for NO2+ formation from concentrated nitric and sulfuric acids.Draw curly arrows from the benzene ring to the electrophile and back from C-H.Identify catalysts such as AlCl3, FeBr3 or FeCl3 used to form electrophiles.
18.5—The mechanism of the electrophilic substitution reactions of benzene in halogenation, nitration and Friedel-Crafts reactions question 1[Maximum number: 4]The synthetic drugs of the 'Caine' family are used as local anaesthetics. Caine drugs prevent nerve activity by binding to sodium channel receptors in the lipid cell membranes of neurons.benzocaineprocainelidocainearticaineLidocaine can be prepared in the synthesis shown.Step 1Step 3lidocaineGive the mechanism for Step 1.Include an equation for the formation of the electrophile.Show AnswerIgnore omission or incorrect placement of methyl groups in M2 and M3HNO3+H2SO4→NO2++HSO4−+H2O\mathrm{HNO}_{3}+\mathrm{H}_{2} \mathrm{SO}_{4} \rightarrow \mathrm{NO}_{2}{ }^{+}+\mathrm{HSO}_{4}{ }^{-}+\mathrm{H}_{2} \mathrm{O}HNO3+H2SO4→NO2++HSO4−+H2OORHNO3+2H2SO4→NO2++2HSO4−+H3O+\mathrm{HNO}_{3}+2 \mathrm{H}_{2} \mathrm{SO}_{4} \rightarrow \mathrm{NO}_{2}{ }^{+}+2 \mathrm{HSO}_{4}{ }^{-}+\mathrm{H}_{3} \mathrm{O}^{+}HNO3+2H2SO4→NO2++2HSO4−+H3O+ORHNO3+H2SO4→H2NO3++HSO4−\mathrm{HNO}_{3}+\mathrm{H}_{2} \mathrm{SO}_{4} \rightarrow \mathrm{H}_{2} \mathrm{NO}_{3}{ }^{+}+\mathrm{HSO}_{4}{ }^{-}HNO3+H2SO4→H2NO3++HSO4−and H2NO3+→NO2++H2O\mathrm{H}_{2} \mathrm{NO}_{3}{ }^{+} \rightarrow \mathrm{NO}_{2}{ }^{+}+\mathrm{H}_{2} \mathrm{O}H2NO3+→NO2++H2O(4)ExpertTE on electrophile from M1 provided positively chargedDo not award lone pair on N of NO2+\mathrm{NO}_{2}{ }^{+}NO2+An answer that makes reference to the following points:- equation for formation of nitronium ion(1)- curly arrow from within hexagon to(1) anywhere on NO2+\mathrm{NO}_{2}{ }^{+}NO2+- structure of intermediate ion(1)- curly arrow from C-H bond to within ring andcorrect productandH+\mathrm{H}^{+}H+(1)Add to Test