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A-Level CAIE Chemistry A237.4 Proton NMR spectroscopyQuestion Bank

[Maximum number: 2]

Serotonin can be synthesised from the amino acid tryptophan in two steps.

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(a)

Serotonin is converted by enzymes in the liver to compound M.

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[ 2 ]
(i)

The proton NMR spectrum of M dissolved in CDCl3\mathrm{CDCl}_{3} shows eight peaks due to the eight different types of proton present in the molecule.

The proton NMR spectrum of M dissolved in D2O\mathrm{D}_{2} \mathrm{O} was recorded.
Predict the number of peaks that would be seen in the proton NMR spectrum of M in D2O\mathrm{D}_{2} \mathrm{O}. Explain your answer.
number of peaks explanation

[ 2 ]
(a)

An ester of pyruvic acid, F, is dissolved in CDCl3\mathrm{CDCl}_{3} and analysed by proton NMR spectroscopy.

F

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The proton NMR spectrum of F is shown.

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Use the proton NMR spectrum of F to complete the table.

Table
[ 3 ]
(b)

Deuterium oxide, D2O\mathrm{D}_{2} \mathrm{O}, where D is 2H{ }^{2} \mathrm{H}, can be used as a solvent in proton NMR spectroscopy. The proton NMR spectrum of alanine in CDCl3\mathrm{CDCl}_{3} has 4 peaks.
The proton NMR spectrum of alanine in D2O\mathrm{D}_{2} \mathrm{O} has 2 peaks.

alanine

alanine

On the diagram of alanine, circle the protons that show peaks in both NMR spectra. Explain your answer.

[ 2 ]
(a)

An ester of pyruvic acid, F, is dissolved in CDCl3\mathrm{CDCl}_{3} and analysed by proton NMR spectroscopy.

F

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The proton NMR spectrum of F is shown.

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Use the proton NMR spectrum of F to complete the table.

Table
[ 3 ]
(b)

Deuterium oxide, D2O\mathrm{D}_{2} \mathrm{O}, where D is 2H{ }^{2} \mathrm{H}, can be used as a solvent in proton NMR spectroscopy. The proton NMR spectrum of alanine in CDCl3\mathrm{CDCl}_{3} has 4 peaks.
The proton NMR spectrum of alanine in D2O\mathrm{D}_{2} \mathrm{O} has 2 peaks.

alanine

alanine

On the diagram of alanine, circle the protons that show peaks in both NMR spectra. Explain your answer.

[ 2 ]
(a)

A sample of benzocaine, shown below, was analysed by proton NMR and carbon- 13 NMR spectroscopy.

[ 7 ]
(i)

Benzocaine was dissolved in CDCl3\mathrm{CDCl}_{3} and the proton NMR spectrum of this solution was recorded.

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Suggest why CDCl3\mathrm{CDCl}_{3} and not CHCl3\mathrm{CHCl}_{3} is used as the solvent when obtaining a proton NMR spectrum.

[ 1 ]
(ii)

Use the Data Booklet and the spectrum in (d)(ii) to complete the table for the proton NMR spectrum of benzocaine. The actual chemical shifts, δ\delta, for the four absorptions have been added.

Table
[ 4 ]
(iii)

Explain the splitting pattern for the absorption at δ1.2ppm\delta 1.2 \mathrm{ppm}.

[ 1 ]
(iv)

The proton NMR spectrum of benzocaine dissolved in D2O\mathrm{D}_{2} \mathrm{O} was recorded.

Suggest how this spectrum would differ from the spectrum in (d)(ii). Explain your answer.

[ 1 ]
(a)

Complete Table 6.2 to predict the number of peaks in the proton (1H)\left({ }^{1} \mathrm{H}\right) NMR spectrum for Dewar benzene, Ladenburg benzene and delocalised benzene.

Table 6.2

Table 6.2

[ 1 ]
(a)

Three carboxylic acids, methanoic acid, HCO2H\mathrm{HCO}_{2} \mathrm{H}, ethanedioic acid, HO2CCO2H\mathrm{HO}_{2} \mathrm{CCO}_{2} \mathrm{H}, and butanedioic acid, HO2CCH2CH2CO2H\mathrm{HO}_{2} \mathrm{CCH}_{2} \mathrm{CH}_{2} \mathrm{CO}_{2} \mathrm{H}, are compared. Two tests were carried out on separate samples of each organic acid, as shown.

The following results were obtained. ✓ = observed change x= no observed reaction

Table
[ 1 ]
(i)

The proton NMR spectrum of HCO2H\mathrm{HCO}_{2} \mathrm{H} in D2O\mathrm{D}_{2} \mathrm{O} is obtained.

Describe and explain the difference observed between this spectrum and the proton NMR spectrum of HCO2H\mathrm{HCO}_{2} \mathrm{H} in (b)(ii).

[ 1 ]
[Maximum number: 7]

Compound F contains the elements carbon, hydrogen and oxygen only. All carbon-carbon bonds in F are single bonds. The structure of F was analysed by mass spectrometry and infra-red and NMR spectroscopy.

(a)

F was dissolved in deuterated trichloromethane, CDCl3\mathrm{CDCl}_{3}, and the proton NMR spectrum of this solution obtained.

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[ 7 ]
(i)

Use the Data Booklet and your answer to (a)(ii) to complete Table 1 for the proton NMR spectrum of F.
The actual chemical shifts for the four absorptions in F have been added for you.

Table 1

Table 1

[ 4 ]
(ii)

Describe and explain the splitting pattern for the absorption at δ=1.4\delta=1.4.

[ 1 ]
(iii)

F was dissolved in D2O\mathrm{D}_{2} \mathrm{O} and the proton NMR spectrum of this new solution obtained. Two of the absorptions in Table 1 were not present in this spectrum.

Which absorptions were not present? and

[ 1 ]
(iv)

Suggest the structure of F.

[ 1 ]
[Maximum number: 3]

Butanedioic acid can be made in a three-step synthesis using ethane as the starting material.

ethane

ethane

A

A

B step 3

butanedioic acid

butanedioic acid

(a)

Methylpropanedioic acid is an isomer of butanedioic acid.

methylpropanedioic acid

methylpropanedioic acid

The proton NMR spectrum of methylpropanedioic acid in CCl4\mathrm{CCl}_{4} is shown. \begin{tabular}{|c|cccccc|c||c|}
\hline
\end{tabular}

[ 3 ]
(i)

Identify the protons in the methylpropanedioic acid molecule that are responsible for each area of the proton NMR spectrum.
δ12.7\delta 12.7δ3.3\delta 3.3δ1.1\delta 1.1

[ 2 ]
(ii)

Name the splitting pattern shown at δ3.3\delta 3.3 and explain how it arises.

The carbon-13 NMR spectra of butanedioic acid, HO2CCH2CH2CO2H\mathrm{HO}_{2} \mathrm{CCH}_{2} \mathrm{CH}_{2} \mathrm{CO}_{2} \mathrm{H}, and methylpropanedioic acid, HO2CCH(CH3)CO2H\mathrm{HO}_{2} \mathrm{CCH}\left(\mathrm{CH}_{3}\right) \mathrm{CO}_{2} \mathrm{H} are different.

[ 1 ]
[Maximum number: 2]

Gallic acid, C7H6O5\mathrm{C}_{7} \mathrm{H}_{6} \mathrm{O}_{5}, is a naturally occurring aromatic molecule.

gallic acid

gallic acid

(a)
(i)

The proton NMR spectrum of gallic acid dissolved in D2O\mathrm{D}_{2} \mathrm{O} is recorded.
- Predict the number of peaks observed and any expected splitting pattern.
- State the expected chemical shift range (δ)(\delta) of each peak predicted.

[ 2 ]
(a)

There are four structural isomers with the molecular formula C5H10O\mathrm{C}_{5} \mathrm{H}_{10} \mathrm{O} that are aldehydes.

[ 6 ]
(i)

Draw the structures of these aldehydes.
P
R
Q

(ii)

The NMR spectrum of one of these isomers contains four absorptions. Which isomer P, Q, R or S gives this spectrum?
isomer

(iii)

Predict the number of absorptions that would be given by each of the other three isomers.

Table
[ 6 ]
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