CAIE A-Level Chemistry A2 34.4 Amino Acids Questions
Practise amino-acid charge forms, peptide structures and electrophoresis predictions from pH and pI.
- Syllabus
- 2028–2030
- Course
- Chemistry 9701
- Level
- A2
Practise amino-acid charge forms, peptide structures and electrophoresis predictions from pH and pI.
Amino acids are molecules that contain −NH2 and -COOH functional groups.
Glycine, H2NCH2COOH, is the simplest stable amino acid.
The isoelectric point of glycine is 6.2.
Define isoelectric point.
pH at which a molecule has no overall charge / is neutral/ is a Zwitterion / charges cancel out
Draw the structure of glycine at pH 4 .
Fig. 6.1 shows two syntheses starting with glycine.
Fig. 6.1
State the essential conditions for reaction 1.
ethanol AND heat in a sealed tube
OR ethanol AND high pressure
Identify the reagent used in reaction 2 .
C6H5COCl/ benzoyl chloride / benzoyl anhydride
A molecule of phenylalanine, R, can react with a molecule of glycine to form two dipeptides, S and T.
S and T are structural isomers.
Draw the structures of these dipeptides. The peptide bond formed should be shown fully displayed.
S
T
The isoelectric point of asparagine, asn, is at pH 5.4 .
Describe the meaning of the term isoelectric point.
the pH at which an amino acid exists as a zwitterion
OR
the pH at which an amino acid has no overall charge
Draw the structure of asparagine at pH 1.0.
Asparagine can polymerise to form poly(asparagine).
Draw the structure of poly(asparagine), showing two repeat units. The peptide linkage should be shown displayed.
M1 peptide bond displayed
M2 rest of the structure correct + continuation bonds
The isoelectric point of lysine, lys, is at pH 9.8.
lysine
Fig. 6.2
A mixture of the dipeptide lys-asn and its two constituent amino acids, asparagine and lysine, is analysed by electrophoresis using a buffer at pH 5.0 . The results obtained are shown in Fig. 6.3.
Fig. 6.3
Suggest identities for the species responsible for spots E, F and G. Explain your answers.
| spot | identity |
|---|---|
| E | Asn |
| F | Lys-Asn |
| G | Lys |
M1 table correctly completed. M2 Lys and Lys-Asn are positively charged OR Asn is (nearly) uncharged. M3 Lys-Asn has the highest Mr.
Table 4.1 shows the structures of sections of three polymers, X, Y and Z.
Each polymer is made from only one type of monomer.
Table 4.1
Amino acids can act as monomers.
State what is meant by the isoelectric point of an amino acid.
pH (where) the species is a zwitterion (is the dominant form)
OR pH (where) the species is (electrically) neutral
OR pH (where) the species has a (net overall) charge of zero
Electrophoresis can be used to separate and identify amino acids.
Table 4.3 shows information about the three amino acids glycine, lysine and glutamic acid.
Table 4.3
A mixture containing these three amino acids is analysed in a buffer solution of pH 6.0 .
Draw and label three spots on Fig. 4.1 to indicate the predicted position of each of these amino acids, gly, lys and glu, after electrophoresis.
Fig. 4.1
M1: Gly correct
M2: Glu and Lys correct
Electrophoresis is repeated using a buffer solution of pH 11 .
Predict how the position of glycine will change, if at all, after electrophoresis.
it would move towards the positive terminal / anode / side / end or to the left
The isoelectric point of lysine, lys, is at pH 9.8.
lysine
Fig. 6.2
A mixture of the dipeptide lys-asn and its two constituent amino acids, asparagine and lysine, is analysed by electrophoresis using a buffer at pH 5.0 . The results obtained are shown in Fig. 6.3.
Fig. 6.3
Suggest identities for the species responsible for spots E, F and G. Explain your answers.
| spot | identity |
|---|---|
| E | Asn |
| F | Lys-Asn |
| G | Lys |
M1 table correctly completed. M2 Lys and Lys-Asn are positively charged OR Asn is (nearly) uncharged. M3 Lys-Asn has the highest Mr.