CAIE A-Level Chemistry 34.1 Primary and Secondary Amines
Practise amine synthesis, acylation and basicity using reagents, product structures and nitrogen lone pairs.
- Syllabus
- 2028–2030
- Course
- Chemistry 9701
- Level
- A2
Practise amine synthesis, acylation and basicity using reagents, product structures and nitrogen lone pairs.
Phenylamine, C6H5NH2, and propylamine, CH3CH2CH2NH2, can be produced by different reduction reactions.
Identify an organic compound that can be converted into CH3CH2CH2NH2 by a reduction reaction. State the reagent for this reaction.
organic compound
reagent
M1: propylamide / propenamide / C2H5CONH2OR propanenitrile / C2H5CN
M2: LiAlH4
Asparagine and aspartic acid are two naturally occurring amino acids. Their structures and isoelectric points are shown in Table 8.1.

Table 8.1
Propanedioic acid, HOOCCH2COOH, is treated with an excess of thionyl chloride, SOCl2. Propanedioyl chloride, ClOCCH2COCl, is formed.
Write an equation for this reaction.
HOOCCH2COOH+2SOCl2→ClOCCH2COCl+2SO2+2HCl
Propanedioyl chloride reacts with an excess of asparagine to form compound G with molecular formula C11H16 N4O8.
Each molecule of compound G has four amide groups.
Draw the structure of compound G.

HOOCCH(CH2CONH2)NHCOCH2CONHCH(CH2CONH2)COOH
M1: three molecules joined, with four correct amide groups only
M2: whole structure correct as above, displayed formula accepted, skeletal formula as below accepted
Copper is a transition element and has atomic number 29.
Ethane-1,2-diamine is a useful reagent in organic chemistry.
Explain how the amino groups in ethane-1,2-diamine allow the molecule to act as a Brønsted-Lowry base.
lone pair receive / accepts a proton / H+
1
1
Write an equation for the reaction of ethane-1,2-diamine with an excess of hydrochloric acid.
HX2NCHX2CHX2NHX2+2HClClHX3NCHX2CHX2NHX3Cl
OR HX2NCHX2CHX2NHX2+2HX+HX3NX+CHX2CHX2NX+HX3
1