CAIE A-Level Chemistry 25.2 Partition Coefficients
Practise defining and calculating equilibrium distribution of a solute between two immiscible solvents.
- Syllabus
- 2028–2030
- Course
- Chemistry 9701
- Level
- A2
Practise defining and calculating equilibrium distribution of a solute between two immiscible solvents.
Define the term partition coefficient, Kpc.
M1 ratio of the concentration of a solute in the two immiscible solvents /liquids
M2 at equilibrium
Kpc of benzoic acid between octan-1-ol and water is 79.4.
A solution of 0.400 g of benzoic acid in 25.0 cm3 octan-1-ol is shaken with 125 cm3 of water. Calculate the mass of benzoic acid extracted into the water layer.
mass of benzoic acid extracted =
M1 79.4=(0.4-x / 25) /(x / 125)
M2 x=0.0237 g [2] min2sf
Kpc of benzophenone, C6H5COC6H5, between octan-1-ol and water is different from the value of Kpc of benzoic acid given in (b)(i).
Explain why.
(higher as) benzophenone is more non-polar/more soluble in octan-1-ol ora
Iodine is found naturally in compounds in many different oxidation states.
Iodide ions, I−, react with acidified H2O2(aq) to form iodine, I2, and water. This reaction mixture is shaken with cyclohexane, C6H12, to extract the I2. Cyclohexane is immiscible with water.
15.0 cm3 of C6H12 is shaken with 20.0 cm3 of an aqueous solution containing I2 until no further change is seen.
It is found that 0.390 g of I2 is extracted into the C6H12.
The partition coefficient of I2 between C6H12 and water, Kpc, is 93.8.
Calculate the mass of I2 that remains in the aqueous layer.
Show your working.
mass of I2 in aqueous layer =
M1: Kpc (93.8) = [I₂(cyclohexane)] ÷ [I₂(aq)]
93.8 = (0.390 / 15) ÷ (x / 20)
M2: mass of I₂(aq), x = 5.54 × 10⁻³ g ecf
Suggest how the value of Kpc of I2 between hexan-2-one, CH3(CH2)3COCH3, and water compares to the value given in (a)(ii). Explain your answer.
Kpc would be lower
- hexan-2-one is more polar (than cyclohexane)
OR hexan-2-one is polar AND cyclohexane is non-polar
- I2 is (therefore) less soluble in hexan-2-one
All three correct for two marks