CAIE A-Level Chemistry 28.5 Stability Constants, Kstab
Practise defining Kstab, writing formation expressions and using stability data in equilibrium calculations.
- Syllabus
- 2028–2030
- Course
- Chemistry 9701
- Level
- A2
Practise defining Kstab, writing formation expressions and using stability data in equilibrium calculations.
(f)Table 1.1 shows values for the stability constants,Kstab ,of some silver(I)complexes.

Table 1.1
(i)Define the stability constant of a complex.
equilibrium constant for the formation of the complex (ion)
in a solvent / water / solution OR from its constituent ions or molecules
(ii)Use the information in Table 1.1 to identify the most stable silver(I)complex.
Explain your answer.
most stable
explanation
[Ag(CN)2]-(aq) AND largest (value of) Kstab
Copper is a transition element and has atomic number 29.
The following equilibrium exists between two complex ions of copper in the +2 oxidation state.
Write the expression for the stability constant, Kstab , for this equilibrium.
Kstab =[CuCl42−]/[Cu(H2O)62+][C/]4
1
1
Copper also forms the complex ions [Cu(NH3)2(H2O)4]2+ and [Cu(en)(H2O)4]2+ where en is the bidentate ligand ethane-1,2-diamine, H2NCH2CH2NH2.
equilibrium 1
equilibrium 2
The table lists the values of stability constants for these two complexes.

What do these Kstab values tell us about the relative positions of equilibria 1 and 2?
equilibrium 2 lies more to the RHS/favours forward reaction more
1
1
An aqueous solution of copper(II) sulfate is a blue colour due to the presence of [Cu(H2O)6]2+ complex ions.
The numerical value of the stability constant, Kstab , of the [Cu(NH3)4(H2O)2]2+ complex ion is 1.40×1013.
Define stability constant.
the equilibrium (constant) for the formation of the complex ion in a solvent from its constituent ions or molecules
Compare the stabilities of the [Cu(H2O)6]2+ and [Cu(NH3)4(H2O)2]2+ complex ions. Explain your answer.
[Cu(NH3)4(H2O)2]2+ AND as Kstab is large OWTTE
Write an expression for the stability constant, Kstab , of the [Cu(NH3)4(H2O)2]2+ complex ion. State the units of the stability constant.
Kstab =
units =
Kstab =[[Cu(NH3)4(H2O)2]2+]/[[Cu(H2O)6]2+][NH3]4[1]mol−4dm12[1] ecf M1
In a particular solution the concentration of the [Cu(NH3)4(H2O)2]2+ complex ion is 0.0074 moldm−3 and the concentration of NH3 is 0.57 moldm−3.
Use your expression in (c)(iii) and the Kstab value 1.40×1013 to calculate the concentration of the [Cu(H2O)6]2+ complex ion in this solution.
concentration of [Cu(H2O)6]2+=moldm−3
[Cu(H2O)6]2+]=(0.0074)÷(1.4×1013×0.574)[Cu(H2O)6]2+]=5.01×10−15 min 2 sf ecf 6(c)( iii )