CAIE A-Level Chemistry A2 37.2 Gas Liquid Chromatography Questions
Practise defining phases and retention time, interpreting peaks and calculating percentage composition.
- Syllabus
- 2028–2030
- Course
- Chemistry 9701
- Level
- A2
Practise defining phases and retention time, interpreting peaks and calculating percentage composition.
Lactic acid, CH3CH(OH)COOH, is the only monomer needed to form the polymer polylactic acid, PLA.
An impure sample of CH3CH(OH)COOH contains pentan-3-one as the only contaminant. The mixture is analysed using gas/liquid chromatography. The pentan-3-one is found to have a longer retention time than the lactic acid.
Explain what is meant by retention time.
time between injection and detection [1]
Suggest suitable substances, or types of substances, that could be used as the mobile and stationary phases.
mobile phase
stationary phase
an unreactive gas AND a non-polar liquid [1]
Describe how the percentage composition of the mixture can be determined from the gas/liquid chromatogram.
area of peak divided by total area of all peaks ×100% [1]
An alkene, a carboxylic acid and a ketone, all of similar volatility, are mixed together. The mixture is then analysed by gas chromatography.
The gas chromatogram produced is shown.
The separation of the three compounds depends on their relative solubilities in the liquid stationary phase. The liquid stationary phase is an alkane.
Complete the table to suggest which compound in the mixture is responsible for each peak J, K and L. Explain your answer by reference to the intermolecular forces of each compound.
A student calculates the areas underneath the three peaks in the chromatogram.
| peak | organic compound | explanation |
|---|---|---|
| J | carboxylic acid | most polar |
| K | ketone | polarity between J and L |
| L | alkene | most non-polar |
The area underneath each peak is proportional to the mass of the respective compound.
Calculate the percentage by mass in the original mixture of the compound responsible for peak K.
\% of mixture responsible for peak K =
Percentage of mixture responsible for peak K: 9218×100%=19.6%.