C2.4 Indices II
- Syllabus
- 0580–2028–2029
- Topic
- C2.4
- Level
- Core
In an, a is the base and n is the index. The index describes repeated multiplication when it is positive, and the same pattern extends consistently to zero and negative indices.
| Index type | Meaning | Example |
|---|---|---|
| positive | multiply the base by itself | 34=3imes3imes3imes3=81 |
| zero | the value is 1 for a non-zero base | 7x0=7imes1=7 |
| negative | take the reciprocal of the matching positive power | x−3=1/x3 for $x |
| e0$ |
Each step down in the index divides by the base: 53=125, 52=25, 51=5, 50=1, 5−1=1/5. This pattern explains both the zero-index and negative-index meanings.
The index applies only to its stated base. In (−2)4, the base is −2, so the value is 16. In −24, the power applies to 2 first, so the value is −16.
A negative index does not make the value negative: y−2=1/y2. It moves a non-zero factor across a fraction bar and changes the sign of the index.
a0=1 and a−n=1/an require $a
e0;divisionbyzeroisundefined.Donotmultiplythebasebytheindex:4^3means4 imes4 imes4,not4 imes3$.
Index laws preserve the meaning of repeated multiplication. First identify the operation and confirm that the bases match; then change the indices using the corresponding rule.
| Structure | Rule | Example |
|---|---|---|
| same base, multiply | aman=am+n | x3x5=x8 |
| same base, divide | am/an=am−n | y3/y5=y−2=1/y2 |
| power of a power | (am)n=amn | (w5)4=w20 |
| power of a product | (ab)n=anbn | (3x2y4)3=27x6y12 |
Treat numerical coefficients separately from variable powers. For 6x7y4imes5x−5y, multiply coefficients and add indices for each matching base: 30x7+(−5)y4+1=30x2y5.
For 12a5÷3a−2, divide coefficients and subtract the denominator index: 4a5−(−2)=4a7. Subtracting a negative index increases the result's index.
To find an unknown index, write both sides with the same base and equate indices. Since 2x=32=25, x=5. Likewise, 912/9w=94 gives 12−w=4, so w=8; logarithms are not required.
Add or subtract indices only when multiplying or dividing powers with the same base. There is no rule that turns am+an into am+n, and (am)n uses multiplication of indices, not addition.