C2.1 Introduction to algebra

Syllabus
0580–2028–2029
Topic
C2.1
Level
Core

Use letters to describe general quantities

A letter can represent any number allowed by a situation. An algebraic expression then describes one calculation that works for every permitted value of that letter.

Notation Meaning Example in context
xx one variable quantity number of pens
60x60x 60 multiplied by xx cost in cents of xx pens at 60 cents each
60x+29y60x+29y sum of two variable costs cost of xx pens and yy rulers
d/nd/n one total shared among nn equal parts cost of one bag when nn bags cost dd dollars

Identify what each letter counts or measures, attach its rate or multiplier, then combine parts using the action in the context. If a team earns 3 points per win and 1 per draw, ww wins and dd draws give 3w+d3w+d points.

Order matters when quantities enter or leave. If a train starts with pp passengers, then xx get off and yy get on, the new number is px+yp-x+y. The expression remains general because it works for any valid pp, xx and yy.

A formula names the quantity produced by an expression. A car hire charge of 56 dollars per day plus a fixed 436 dollars can be written C=56d+436C=56d+436, where CC is the total cost for dd days.

Adjacent symbols indicate multiplication: 60x60x means 60×x60\times x, not the two-digit number '60x'. A letter does not always mean one fixed unknown; it may vary across cases. Keep units consistent before forming a general expression.

Substitute values into expressions and formulas

Substitution replaces each letter with its given numerical value while preserving the original operations, brackets and powers.

Step Action Check
1 write the expression or formula unchanged every symbol is present
2 replace each letter with its value in brackets negative values stay grouped
3 evaluate powers, then multiplication/division, then addition/subtraction follow operation order
4 attach the required unit and apply requested rounding interpret the result

For s=ut+12at2s=ut+\dfrac12at^2 with u=5.2u=5.2, t=7t=7 and a=1.6a=1.6, substitute first: s=5.2(7)+12(1.6)(7)2=36.4+39.2=75.6s=5.2(7)+\dfrac12(1.6)(7)^2=36.4+39.2=75.6. The square applies to the substituted value of tt.

Brackets protect signs. For 8x3y8x-3y with x=5x=5 and y=2y=-2, write 8(5)3(2)=40+6=468(5)-3(-2)=40+6=46. Without brackets, the second negative can be lost.

If a formula needs an intermediate quantity, calculate it explicitly. For M=2.5ATM=2.5AT, a rectangle 1.9 m by 0.6 m has A=1.9×0.6=1.14A=1.9\times0.6=1.14 m²; with T=8T=8, M=2.5(1.14)(8)=22.8M=2.5(1.14)(8)=22.8 kg.

Substitution evaluates a given expression; it does not change the formula or solve for a different letter. In 3t23t^2, square only tt before multiplying by 3, and for t=4t=-4 use 3(4)23(-4)^2, not 3(42)3(-4^2).