D.3.5—Force on current conductor

Syllabus
First assessment 2025
Objective
Level
SL

Calculate Force on a Current-Carrying Conductor

Use the conductor equation

Here LL is only the conductor length inside the uniform field and θ\theta is the angle between conventional current and the field. Direction follows the force rule for conventional current.

F=BIL\sin\theta

Worked example — measuring a field

A perpendicular wire carries I=1.64AI=1.64\,\mathrm{A} through L=8.13cm=0.0813mL=8.13\,\mathrm{cm}=0.0813\,\mathrm{m} and experiences F=4.12×104NF=4.12\times10^{-4}\,\mathrm{N}. Thus B=F/(IL)=(4.12×104)/(1.64×0.0813)=3.09×103TB=F/(IL)=(4.12\times10^{-4})/(1.64\times0.0813)=3.09\times10^{-3}\,\mathrm{T}.

Read the angle limits

The force is zero when the wire is parallel to the field and maximum when it is perpendicular. Use conventional current direction for the force rule, not the electron drift direction.

Connect the models

The conductor formula is the combined magnetic force on moving charge carriers: I=q/tI=q/t and L=vtL=vt lead from F=qvBsinθF=qvB\sin\theta to F=BILsinθF=BIL\sin\theta.

Common trap

Do not use electron motion as the current direction, and do not include wire length outside the region where the magnetic field exists.

D.3.5 Exam Analysis

Assessment in practice

1 marks
How it is assessed

Questions calculate current or field strength from conductor force, length and magnetic field.

Command terms

Show that / What is

What earns marks

Use F=BIL sinθ with conventional current, field-region length and the angle between current and field.

Watch for

Using electron direction instead of conventional current, or using the total wire length rather than the length in the field.

Representative question

Question 1

[Maximum number: 1]

A wire carrying a current I is at right angles to a uniform magnetic field of strength B.

A magnetic force F is exerted on the wire. Which force acts when the same wire is placed at right angles to a uniform magnetic field of strength 2 B when the current is I4?\frac{I}{4} ?

A

F4\frac{F}{4}

B

F2\frac{F}{2}

C

F

D

2 F