C.3.7—Path difference

Syllabus
First assessment 2025
Objective
Level
SL

Use Path Difference for Interference

Define path difference

Path difference is the difference between the distances travelled by two waves from their sources to the same observation point. For in-phase coherent sources, it determines whether the waves arrive in phase or out of phase.

Apply the conditions

Constructive interference occurs when path difference =nλ=n\lambda. Destructive interference occurs when path difference =(n+12)λ=(n+\tfrac12)\lambda, where nn is a whole number.

Count fringes carefully

Start from the central bright fringe when the path difference is zero. Each additional bright fringe changes the path difference by λ\lambda; dark fringes lie halfway between adjacent bright conditions.

Common trap

Do not assign λ/2\lambda/2 to every dark point. The first dark condition is λ/2\lambda/2, then 3λ/23\lambda/2, 5λ/25\lambda/2, and so on.

C.3.7 Exam Analysis

Assessment in practice

1 marks
How it is assessed

Questions ask for path difference at a dark fringe after a stated number of bright or dark fringes. The evidence rewards counting from the central maximum and choosing the half-integer condition for darkness.

Command terms

What is

What earns marks

Identify the central bright condition as zero path difference, count the bright/dark fringes between the reference and target points, and apply nλ for bright or (n + 1/2)λ for dark.

Watch for

Choosing an integer multiple of λ for a dark fringe or losing the extra half-cycle when counting intervening fringes.

Representative question

Question 1

[Maximum number: 1]

In a double-slit experiment using coherent light of wavelength λ\lambda, the central bright fringe is observed on a screen at point P. A point of destructive interference occurs at point Q. Only one point of constructive interference is observed between P and Q.

What is the path difference at Q ?

A

λ2\frac{\lambda}{2}

B

λ\lambda

C

3λ2\frac{3 \lambda}{2}

D

2λ2 \lambda