IB Physics HL E 2 9 Hl Compton Wavelength Shift

[Maximum number: 3]

(a)

Show that the energy of the scattered photon is about 0.17 MeV .

[ 1 ]

$E=<\frac{h c}{\lambda}=>\frac{1.24 \times 10^{-6}}{7.47 \times 10^{-12}}$ OR 0.166 MeV

(b)

For an electron, $\frac{h}{m_{\mathrm{e}} c}=2.43 \times 10^{-12} \mathrm{~m}$ . Determine $\theta$ .

[ 2 ]

$7.47 \times 10^{-12}-6.40 \times 10^{-12}=2.43 \times 10^{-12}(1-\cos \theta)^{}$

« $\cos \theta=0.5597$ so » $\theta=56.0^{\underline{\mathrm{o}}}$

Accept angle in radians ( 0.98 « rad »).

Award [2] if 56 « ${ }^{\circ}$ » or 0.98 « rad» are seen as the answer without working

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IB Physics HL E 2 9 Hl Compton Wavelength Shift Topic Practice

Question 1

Question (a)

Question (b)