IB Physics HL E 2 3 Hl Photoelectric Equation Questions

attempted use of gradient $\left(\frac{h}{e}\right)$ to evaluate h;
eg $\frac{2.4}{6 \times 10^{14}}=4 \times 10^{-15} \mathrm{eVs}$; (allow answers in the range of 3.9 to $4.2 \times 10^{-15}$ ) $6.4 \times 10^{-34} \mathrm{Js}$; (allow ECF, eg answers in the range of 6.2 to $6.7 \times 10^{-34}$ )

Marking guidance:

Do not allow a bald answer of $6.6 \times 10^{-34}$ as value is known.
or
use of y-intercept $=\frac{-h f_{0}}{e}$;
$h=\frac{3.77 \times 1.6 \times 10^{-19}}{0.93 \times 10^{15}} ;($ allow intercept between -3.6 and -3.8 eV)
$6.4 \times 10^{-34} \mathrm{Js}$; (allow ECF, eg answers in the range of 6.0 to $6.8 \times 10^{-34}$ )
Do not allow a bald answer of $6.6 \times 10^{-34}$ as value is known.

$E=6.62 \times 10^{-34} \times 9.3 \times 10^{14}\left(=6.2 \times 10^{-19} \mathrm{~J}\right)$;
an answer in the range of 3.4 to 4.0 eV ;
(allow ECF from (e)(i) and (e)(ii))
or
identifies y intercept as work function;
an answer in the range of 3.6 to 3.8 eV ;