E.3.12—Half-life changes

Syllabus
First assessment 2025
Objective
Level
HL

Calculate Half-Life Changes

Use integer half-lives

If activity changes from A0A_0 to AA, use A/A0=(1/2)nA/A_0=(1/2)^n to find the number of half-lives nn. For example, a fall to one-eighth means three half-lives.

Worked example — integer half-lives

A net count rate falls from 640s1640\,\mathrm{s^{-1}} to 80s180\,\mathrm{s^{-1}} in 18 h. Since 80/640=1/8=(1/2)380/640=1/8=(1/2)^3, three half-lives elapsed. Therefore T1/2=18/3=6.0hT_{1/2}=18/3=6.0\,\mathrm{h}.

Find the half-life

Once nn is known, divide the elapsed time by nn: T1/2=t/nT_{1/2}=t/n. This is often quicker and clearer than starting with the exponential form.

Check the direction

A decay interval must reduce activity or count rate. If the calculated half-life or number of half-lives implies growth, revisit the ratio.

Common trap

Do not call a drop to one-eighth “one half-life”; half-life is the time for one factor of one-half.

E.3.12 Exam Analysis

Assessment in practice

1–2 marks
How it is assessed

Questions calculate tritium half-life from an activity reduction to one-eighth over a stated time.

Command terms

Calculate

What earns marks

Recognise one-eighth as three half-lives, then divide the time by three and include units.

Watch for

Treating one-eighth as two half-lives or using the final fraction as the half-life itself.