E.1.11 (HL)—Bohr angular momentum

Syllabus
First assessment 2025
Objective
Level
HL

Apply Bohr Quantization

HL only

Apply the angular-momentum condition

The Bohr model permits only integer values of n=1,2,3,n=1,2,3,\ldots. The electron's orbital angular momentum is therefore quantized rather than continuously variable.

L=mvr=\frac{nh}{2\pi}

Worked example — n=4n=4

For n=4n=4, L=4h/(2π)=4(6.63×1034)/(2π)=4.22×1034kgm2s1L=4h/(2\pi)=4(6.63\times10^{-34})/(2\pi)=4.22\times10^{-34}\,\mathrm{kg\,m^2\,s^{-1}}. An intermediate value is not an allowed Bohr-orbit angular momentum.

Connect quantization to energy

Only selected radii, speeds and total energies are allowed. The electron cannot occupy an intermediate orbit energy in this model, which explains discrete atomic levels and line spectra.

Use ratios efficiently

For hydrogen, combining the quantization condition with the electrostatic circular-orbit model gives rnn2r_n\propto n^2 and vn1/nv_n\propto 1/n. If r2/r1=4r_2/r_1=4, then v2/v1=1/2v_2/v_1=1/2.

Common trap

Do not say that quantization fixes only the radius. The condition restricts angular momentum and leads to discrete allowed energies; do not treat mvrmvr as an arbitrary continuous value.

E.1.11 (HL) Exam Analysis

HL only

Assessment in practice

1–2 marks
How it is assessed

Questions ask for the consequence of quantization or use radius and energy relationships to compare electron speeds in different states.

Command terms

Outline / Determine

What earns marks

State that energy is discrete, then use the correct proportional relationship or quantization condition for a ratio calculation.

Watch for

Saying that the energy remains continuous or using v proportional to r instead of the inverse square-root or inverse-n relationship required by the model.