C.1.4—Period, frequency and angular frequency
- Syllabus
- First assessment 2025
- Objective
- —
- Level
- HL
Three equivalent measures
T=f1=ω2π,ω=2πf
Use seconds for T, hertz for f, and radians per second for ω.
Worked example from the mapped local textbook
A guitar-string point oscillates at f=196Hz.
T=1961=5.10×10−3s
ω=2π(196)=1.23×103rads−1
Common trap
Do not mix this general conversion objective with the separate spring and pendulum period models. Also, ω is 2π times f, not f/(2π).
Questions ask you to infer a period from a graph or determine how a pendulum frequency changes when length changes. The evidence rewards the correct square-root dependence for the model and the correct T–f–ω conversion.
Determine / What is
Write T = 1/f = 2π/ω before substituting. Keep T in seconds, f in hertz and ω in rad s−1. For a pendulum or spring, first calculate the model’s period, then convert to the requested frequency.
Using a direct inverse-length relationship for a pendulum instead of f ∝ 1/√l, or forgetting the factor 2π when converting f to ω.
Representative question
Determine the time period of the system when a is small.
attempted use of ω2=(−)xa
suitable read-offs leading to gradient of line =28 《 s−2 》
T=ω2π↔=282π↔∨T=1.2 s
Recognize SHM
SHM requires a restoring acceleration a=−ω2x about equilibrium. Track displacement, amplitude, period, frequency and angular frequency with T=1/f=2π/ω.
Track one cycle
At an extreme, potential energy is maximum and kinetic energy is zero; at equilibrium, kinetic energy is maximum and potential energy is minimum. Total energy remains constant in ideal SHM.
Read the motion
The gradient of a displacement–time graph is velocity. Acceleration is opposite to displacement. Use the sign of displacement and the gradient to identify direction at any instant.
Final check
Measure displacement from equilibrium, keep amplitude distinct from peak-to-peak distance, and name the relevant potential-energy form for the oscillator.