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IB Chemistry SL 1.4.3 Molar Mass M Questions

Use a formula to obtain molar mass, then apply n=m/M and Avogadro constant to convert between mass, amount and specified particles.

Syllabus
First assessment 2025
Course
Chemistry SL
Level
SL

Exam points

  • Calculate molar mass in g mol⁻¹ from a chemical formula, including hydrates and organic compounds.
  • Use n=m/M to convert between mass and amount in mol, then combine with stoichiometric coefficients in reaction calculations.
  • Convert amount or mass to specified particles using molar mass and Avogadro constant, checking units and significant figures.

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Study 1.4.3—Molar mass (M) conceptsOpen the corresponding Concept lesson for explanations, examples and exam connections.

IB Chemistry SL 1.4.3 Molar Mass M Questions question 1

[Maximum number: 1]

Chlorine undergoes many reactions.

2.67 g of manganese(IV) oxide was added to 200.0 cm3200.0 \mathrm{~cm}^{3} of 2.00moldmm−3HCl2.00 \mathrm{moldm} \mathrm{m}^{-3} \mathrm{HCl}.

MnO2( s)+4HCl(aq)→Cl2( g)+2H2O(l)+MnCl2(aq)\mathrm{MnO}_{2}(\mathrm{~s})+4 \mathrm{HCl}(\mathrm{aq}) \rightarrow \mathrm{Cl}_{2}(\mathrm{~g})+2 \mathrm{H}_{2} \mathrm{O}(\mathrm{l})+\mathrm{MnCl}_{2}(\mathrm{aq})

Calculate the amount, in mol, of manganese(IV) oxide added.

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