IB Chemistry SL 1.2 The Nuclear Atom Question Bank

Practise IB Chemistry SL 1.2 with evidence-led questions on atomic structure, isotopes, nuclei and mass spectrometry.

[Maximum number: 1]

Titanium is a transition metal.

State the number of protons, neutrons and electrons in the ${ }_{22}^{48} \mathrm{Ti}$ atom.

Protons:

Neutrons:

Electrons:

[Maximum number: 6]

Chlorine occurs in Group 7, the halogens.

(a)

Two stable isotopes of chlorine are ${ }^{35} \mathrm{Cl}$ and ${ }^{37} \mathrm{Cl}$ with mass numbers 35 and 37 respectively.

[ 6 ]

(i)

Define the term isotopes of an element.

[ 2 ]

(ii)

Calculate the number of protons, neutrons and electrons in the isotopes ${ }^{35} \mathrm{Cl}$ and ${ }^{37} \mathrm{Cl}$ .

Table for Question (ii) — IB Chemistry SL

[ 2 ]

Isotope

Number of

protons

Number of

neutrons

Number of

electrons

${ }^{35} \mathrm{Cl}$

17

18

${ }^{37} \mathrm{Cl}$

17

20

Marking guidance:

Allow [1 max] for 17 p, 17 e for both if n's are omitted or incorrect.
Allow [1 max] for ${ }^{35} \mathrm{Cl}$ : 18 n and ${ }^{37} \mathrm{Cl}$ : 20 n if p 's and e 's are omitted.

(iii)

Using the mass numbers of the two isotopes and the relative atomic mass of chlorine from Table 5 of the Data Booklet, determine the percentage abundance of each isotope.

Percentage abundance ${ }^{35} \mathrm{Cl}$ :

Percentage abundance ${ }^{37} \mathrm{Cl}$ :

[ 2 ]

$\left(\right.$ for $\left.{ }^{35} \mathrm{Cl}: x \%\right) 35 x+3700-37 x=3545$ ;

Marking guidance:

Allow other alternative mathematical arrangements.
${ }^{35} \mathrm{Cl}=77.5 \%$ and ${ }^{37} \mathrm{Cl}=22.5 \%$ ;

Award [1 max] for correct percentages if no correct working is shown.

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IB Chemistry SL 1.2 The Nuclear Atom Question Bank

Exam points

Covered syllabus points

Covered syllabus points

1.2 The nuclear atom question 1

1.2 The nuclear atom question 2

Question (a)

Question (i)

Question (ii)

Question (iii)