IB Chemistry SL 1.2 The Nuclear Atom Questions
Practise IB Chemistry SL 1.2 with evidence-led questions on atomic structure, isotopes, nuclei and mass spectrometry.
- Syllabus
- First assessment 2025
- Course
- Chemistry SL
- Level
- SL
Practise IB Chemistry SL 1.2 with evidence-led questions on atomic structure, isotopes, nuclei and mass spectrometry.
Titanium is a transition metal.
Titanium exists as several isotopes. The mass spectrum of a sample of titanium gave the following data:
Calculate the relative atomic mass of titanium to two decimal places.
100(46×7.98)+(47×7.32)+(48×73.99)+(49×5.46)+(50×5.25)=47.93
Answer must have two decimal places with a value from 47.90 to 48.00.
Award [2] for correct final answer.
Award [0] for 47.87, the data booklet value.
State the number of protons, neutrons and electrons in the 2248Ti atom.
Protons:
Neutrons:
Electrons:
Protons: 22 AND Neutrons: 26 AND Electrons: 22
The element boron has two naturally occurring isotopes, 10 B and 11 B.
Define the term isotopes of an element.
atoms of the same element/with the same number of protons/with same atomic number but different number of neutrons/mass number/mass;
Calculate the percentage abundance of each isotope, given that the relative atomic mass of B is 10.81 .
10x+11(1−x)=10.81,x=0.19;
Marking guidance:
Accept similar method.
10B:19% and 11B:81%;
The percentage abundance of the isotopes of boron can be determined with a mass spectrometer. The diagram shows the operation of a mass spectrometer.
Deduce the number of protons, neutrons and the electron arrangement of the main ion of 11 B formed in stage Q.
Protons:
Neutrons:
Electron arrangement:
Protons: 5 and Neutrons: 6;
Electron arrangement: 2,2/1 s22 s2;
Marking guidance:
Allow suitable diagram.