B3.1 Gas exchange
Gas exchange links animal ventilation, alveolar diffusion, leaf stomata, transpiration and haemoglobin affinity to oxygen supply and carbon dioxide removal.
- Syllabus
- First assessment 2025
- Topic
- B3.1
- Level
- HL
Gas exchange links animal ventilation, alveolar diffusion, leaf stomata, transpiration and haemoglobin affinity to oxygen supply and carbon dioxide removal.
Gas exchange is the diffusion of oxygen, carbon dioxide or other gases between an organism and its environment.
Cells need oxygen for aerobic respiration and must remove carbon dioxide. Diffusion is effective only across a surface where a gradient exists and the path is short enough.
Check: gas; source and destination; concentration or partial-pressure gradient; distance crossed.
Oxygen moves from alveolar air into blood while carbon dioxide moves in the opposite direction.
Gas exchange is not the same as ventilation or circulation: those processes help maintain the gradient but are not the crossing event.
This objective is assessed through structured response, commonly using Describe / Distinguish / Explain.
Describe / Distinguish / Explain / Outline
Build the answer around this relationship: Aerobic cell respiration requires oxygen and produces carbon dioxide that must be removed.
Confusing ventilation with gas exchange or with cell respiration rather than separating air movement, diffusion and energy release.
Representative question
Outline the process of gas exchange necessary for aerobic respiration in a unicellular eukaryotic organism.
a. oxygen must be taken up AND carbon dioxide must be released
b. gases pass through a cell membrane by simple diffusion
c. require a concentration gradient
OR pass from high concentration to low concentration
d. without requiring energy
OR passive process
e. large SA: vol ratio
Both needed.
3 max
Question
Answers
Notes
Total
A good gas-exchange surface has a large area, a short diffusion distance and a moist barrier that gases can dissolve in.
A large area provides more parallel routes, thinness shortens travel time and moisture allows gas molecules to enter solution before crossing cells. Maintaining a gradient completes the design.
Evaluate a surface using: area; thickness; moisture; permeability; and gradient maintenance.
Alveoli combine a huge surface, one-cell-thick epithelium and moist lining, so oxygen can diffuse rapidly into nearby capillaries.
Large area alone is insufficient if the barrier is thick or the gradient is lost.
This objective is assessed through structured response, commonly using State / Describe / Explain.
State / Describe / Explain
Build the answer around this relationship: Large surface area increases the amount of gas that can diffuse at once.
Listing alveolar features without linking each feature to faster diffusion.
Representative question
Explain the process of gas exchange taking place in the alveoli.
a. O2 diffuses into blood and CO2 diffuses out from blood
b. blood entering the alveoli is high in CO2 /low in O2
OR
air in alveolus is high in O2 /low in CO2
c. diffusion (in either direction) take place due to concentration gradients
d. concentration gradients maintained by ventilation/blood flow
e. large surface area created by many alveoli/spherical shape of alveoli for more efficient diffusion
f. rich supply of capillaries (around alveoli) allows efficient exchange
g. type I pneumocytes are thin to allow easy diffusion/short distances
h. gases must dissolve in liquid lining of alveolus in order to be exchanged
i. type II pneumocytes secrete surfactants to reduce surface tension/prevent lungs sticking together
j. type II pneumocytes create moist conditions in alveoli
Explain
7 max
Net gas diffusion continues when ventilation, blood flow or photosynthetic uptake continually removes gas from one side of the surface.
If both sides approach the same concentration, random movement continues but net transfer falls. Renewal of air or fluid restores the difference that drives net movement.
Trace the chain: gas enters; a gradient drives diffusion; ventilation, circulation or metabolism renews the gradient.
Fresh air reaching an alveolus keeps oxygen higher in the air than in incoming blood, sustaining oxygen uptake.
A concentration gradient is not maintained by diffusion itself; another flow or reaction must renew it.
This objective is assessed through structured response, commonly using Explain / Describe.
Explain / Describe
Build the answer around this relationship: Ventilation refreshes alveolar air so oxygen remains high and carbon dioxide remains low.
Referring only to oxygen concentration at altitude instead of oxygen partial pressure.
Representative question
Describe how a concentration gradient of oxygen is maintained between the lungs and blood capillaries.
a. gas exchange takes place between the alveoli and capillaries;
b. alveoli surrounded by (dense) network of blood capillaries;
c. blood returning to alveolar capillaries is low in oxygen;
d. ventilation brings air rich in oxygen into the alveoli/lungs;
e. there is a higher concentration of oxygen in alveoli than in blood capillaries;
f. oxygen diffuses from alveoli/lungs to capillaries (moves down a concentration gradient);
e. Accept converse.
4 max
Mammalian lungs use branching airways, many alveoli, thin epithelium and dense capillaries to maximize gas exchange.
Branching distributes air, alveoli create area, the thin alveolar-capillary barrier shortens diffusion distance and blood flow carries gases away. Elastic tissue and surfactant support repeated ventilation.
Link adaptation to function: bronchioles distribute; alveoli add area; thin walls shorten distance; capillaries maintain gradients.
A red blood cell passing through an alveolar capillary encounters oxygen-rich air across a very thin moist barrier.
Lung adaptations work together; naming one feature without its mechanism does not explain efficient exchange.
This objective is assessed through structured response, commonly using Describe / Explain / Outline.
Describe / Explain / Outline / Identify / Predict
Build the answer around this relationship: Many alveoli create a large surface area for diffusion.
Treating alveoli as muscular structures rather than thin exchange surfaces supported by ventilation and elastic recoil.
Representative question
A supply of oxygen is needed for aerobic respiration in mitochondria. Describe the features of alveoli in human lungs that adapt them for efficient absorption of oxygen.
large surface area from having many alveoli; single/flattened layer of (thin) cells in wall; Reject one-cell membrane/thin membrane. (surrounded by) dense network of capillaries/capillary bed; short distance for gases/oxygen/carbon dioxide to diffuse; moist lining / film of moisture on inside of alveolus; moisture allows oxygen/gases to dissolve; diffusion of oxygen down concentration gradient;
Ventilation moves fresh air into and stale air out of the lungs, renewing alveolar concentration gradients.
Inspiration increases thoracic volume and lowers pressure so air enters; expiration reverses the pressure difference. Elastic recoil and muscle action return the lungs toward resting volume.
Trace: thoracic volume change; pressure change; air movement; refreshed alveolar gradient.
When the diaphragm contracts and flattens, thoracic volume rises, pressure falls and air flows into the lungs.
Air moves because of pressure differences, not because the diaphragm pushes air directly.
This objective is assessed through structured response, commonly using Explain / Outline / Identify.
Explain / Outline / Identify / Describe / State
Build the answer around this relationship: Inhalation occurs when diaphragm and external intercostal contraction increases thoracic volume.
Reversing the pressure change during inhalation by saying contraction raises thoracic pressure.
Representative question
Explain the mechanism of ventilation in the lungs in order to promote gas exchange for cell respiration.
inspiration/inhalation brings air into lungs; external intercostal muscles contract; and move rib cage upwards and outwards;
diaphragm flattens/contracts;
increasing thoracic volume; pressure decreases from atmospheric pressure so air rushes into lungs; expiration/exhalation forces air out;
internal intercostal muscles contract / external intercostal muscles and diaphragm relax; abdominal/abdomen wall muscles contract and push diaphragm upwards;
decreasing thoracic volume;
increasing pressure in lungs so air is forced out;
a concentration gradient between air sacs and blood needs to be maintained;
Spirometry records changes in air moved during breathing, allowing volumes such as tidal and vital capacity to be estimated.
A spirometer measures the volume entering or leaving the apparatus over time. It cannot directly measure residual volume that remains after maximal expiration, so some capacities need indirect methods.
Interpret a trace by identifying baseline, peaks and troughs, then match the measured change to the volume definition.
The difference between a maximal inhalation and maximal exhalation trace estimates vital capacity, not total lung capacity.
A larger trace does not automatically mean healthier lungs; effort, technique and the exact volume being measured matter.
This objective is assessed through structured response, commonly using Define / State / Calculate.
Define / State / Calculate / Compare / Describe / Outline
Build the answer around this relationship: Tidal volume is the volume of air moved during one normal breath.
Giving a ventilation-rate number without breaths per minute or another valid time unit.
Representative question
Outline how ventilation rate could have been monitored in this study.
a. «data logging» with spirometer
OR
chest belt
b. «tidal» volume recorded for a given period of time
OR average «tidal» volume found and multiplied by number breaths per minute
Marking guidance:
Do not accept confusion with respirometer (measuring oxygen consumption or CO2 release).
Must include a reference to time.
Leaves use stomata and internal air spaces to exchange carbon dioxide and oxygen, while a waxy cuticle and guard cells limit water loss.
Spongy mesophyll air spaces expose moist cell surfaces to gases. Stomata open when carbon dioxide uptake is valuable but closing reduces transpiration, creating a real trade-off.
Explain a leaf adaptation by linking: route for gas; photosynthetic demand; water-loss cost.
Opening stomata in daylight can increase carbon-dioxide entry for photosynthesis but also increases water-vapor loss.
Stomata do not maximize gas exchange all the time; guard-cell control balances carbon gain against dehydration.
This objective is assessed through structured response, commonly using Identify / Explain.
Identify / Explain
Build the answer around this relationship: Stomata allow carbon dioxide, oxygen and water vapour to diffuse through the epidermis.
Calling any pore a stoma without identifying the guard-cell opening through the epidermis.
Representative question
Explain the roles of two leaf structures that help with the process of gas exchange in the leaf.
a. spongy mesophyll provides a large/moist/permeable surface area (for gas exchange);
b. guard cells form pores/stomata (through the epidermis) / open and close stomata OR stomata are pores (through the epidermis that) allow CO2/O2/ gases to enter/exit the leaf/to pass through the epidermis;
c. (air) spaces for diffusion/movement/transfer of gases (to/from spongy mesophyll cells and stomata);
2 max
In a dicot leaf, air spaces and mesophyll arrangement create short routes from stomata to photosynthetic cells, while vascular tissue supplies and removes materials.
Palisade cells near the upper surface capture light; spongy mesophyll spaces allow gases to spread internally; veins connect the leaf to water and sugar transport.
Read a leaf cross-section by mapping: surface protection; photosynthetic tissue; air spaces; vascular bundle; stomatal route. Then link each position to movement.
Carbon dioxide entering a lower-surface stoma diffuses through spongy-air spaces before reaching mesophyll cells, where photosynthesis consumes it.
A tissue’s position is not its function by itself; explain how its structure changes a diffusion or transport path.
This objective is assessed through structured response, commonly using Draw / Explain.
Draw / Explain
Build the answer around this relationship: Palisade mesophyll lies near the upper leaf surface and is rich in chloroplasts.
Drawing individual cell detail when a plan diagram should show tissue distribution and relative positions.
Representative question
Explain how the distribution of tissues in the leaf of a dicotyledonous plant is adapted to production and distribution of products of photosynthesis.
a. leaf has large surface area for absorption of light;
b. upper epidermis (thin) allowing light to pass;
c. (waxy translucent) cuticle to (allow light in and) prevent water loss;
d. palisade mesophyll contains many (cells with) chloroplasts;
e. palisade mesophyll close to upper layer to receive more light;
f. spongy mesophyll contains chloroplasts which allow photosynthesis;
g. spongy mesophyll (cells loosely packed) allows gaseous exchange;
h. stoma allow CO2 for photosynthesis to diffuse in;
i. stoma allow O2 produced in photosynthesis to diffuse out;
j. xylem brings water (for reactions);
k. phloem carries away products of photosynthesis/sucrose;
1. guard cells open and close stoma (for gas exchange);
Marking guidance:
Award marks to an annotated diagram explaining the above points.
Transpiration is the loss of water vapor from leaves, mainly through stomata, and it helps create a pull that draws water upward through xylem.
Evaporation lowers water potential in leaf air spaces. Cohesion between water molecules transmits tension through the continuous xylem column, linking leaf loss to root uptake.
Trace: evaporation; lower leaf water potential; cohesion/tension; upward xylem flow.
On a dry, windy day, faster evaporation can increase transpiration and the pull on the xylem stream.
Transpiration is water loss, not water absorption; roots supply water but stomata regulate the major exit.
This objective is assessed through structured response, commonly using Explain / Outline / Suggest.
Explain / Outline / Suggest / Define / Compare
Build the answer around this relationship: Transpiration involves evaporation from leaf surfaces followed by diffusion through stomata.
Assuming a potometer directly measures water lost rather than estimating it from water uptake.
Representative question
Explain how abiotic factors affect the rate of transpiration in terrestrial plants.
a. less transpiration/water loss as (atmospheric) humidity rises;
b. air spaces inside leaf are saturated/nearly saturated (with water vapour);
c. smaller concentration gradient with higher atmospheric humidity;
d. more transpiration/water loss as temperature rises/with more heat;
e. faster diffusion / more kinetic energy (of water molecules);
f. faster evaporation (due to more latent heat available);
g. more transpiration/water loss as wind (speed) increases;
h. humid air/water vapour blown away from the leaf;
i. increasing the concentration gradient (of water vapour); j. more transpiration/water loss in the light; k. light causes stomata to open / stomata closed in darkness;
I. Iow CO2 concentration inside leaf in bright light so stomata open wider; Accept any of the points if clearly made on an annotated graph.
Stomatal density is the number of stomata per unit leaf area; comparing densities can indicate potential routes for gas exchange and water loss.
More stomata can increase the maximum conductance of a leaf, but actual exchange also depends on aperture, humidity, wind, light and gradients.
Compare samples using: count; same area; same surface; then separate potential density from actual opening.
A leaf with 20 stomata per mm² has twice the density of one with 10 per mm², but it may lose less water if most pores are closed.
Stomatal density is not a direct measurement of photosynthesis or transpiration rate.
This objective is assessed through structured response, commonly using Outline.
Outline
Build the answer around this relationship: Stomatal density is calculated as the number of stomata divided by leaf area observed.
Representative question
Outline how stomatal density in busy Lizzie leaves can be estimated within a known field of view.
(count) number of stomata (within field of view / image) AND divide by the area / field of view;
Core gas-exchange answers link exchange surfaces to diffusion gradients. For animals, exchange surfaces are explained by diffusion properties, ventilation, and blood flow. For plants, leaves allow carbon dioxide entry and oxygen/water vapour exit while controlling water loss through stomata. Spirometry, transpiration, and stomatal density data provide evidence of gradient and surface-area effects.
Haemoglobin binds oxygen reversibly in lungs and releases it in tissues, with its subunits enabling efficient loading and unloading.
In the lungs, high oxygen partial pressure favors binding. In respiring tissues, lower oxygen and altered conditions favor release, so haemoglobin transports rather than permanently stores oxygen.
Interpret a binding claim by checking: oxygen partial pressure; affinity; loading site; unloading tissue. These conditions change along the circulation.
Blood leaving the lungs carries more oxyhaemoglobin than blood arriving from oxygen-consuming muscle because the lungs provide a higher oxygen partial pressure.
High haemoglobin affinity is not always best: oxygen must also be released where cells need it.
This objective is assessed through structured response, commonly using Outline / Describe / Suggest.
Outline / Describe / Suggest
Build the answer around this relationship: Oxygen binds reversibly to haem groups containing iron in haemoglobin.
Describing foetal haemoglobin as having lower affinity instead of a left-shifted, higher-affinity curve.
Representative question
Suggest how changes in hemoglobin could help humans become better adapted to living at high altitude.
a. induced conformational change in the structure of the hemoglobin molecule occurs
b. «this» hemoglobin has higher affinity for oxygen
c. saturation curve shifted to the left «because of low O2 levels»
d. «this» hemoglobin becomes more saturated at lower partial pressures of oxygen
e. increased hematocrit/concentration of hemoglobin/red blood cells to carry more O2
Marking guidance:
Allow answers in an annotated diagram.
3 max
The Bohr shift is the reduced oxygen affinity of haemoglobin when carbon dioxide rises and pH falls, promoting oxygen release in respiring tissues.
Respiration produces carbon dioxide, which forms carbonic acid and increases H⁺. These changes stabilize the lower-affinity form of haemoglobin, shifting the dissociation curve right.
Trace: more respiration; CO₂ and H⁺ rise; affinity falls; unloading increases.
During exercise, muscle CO₂ production rises, so haemoglobin releases more oxygen at the same tissue partial pressure.
The Bohr shift changes affinity, not the amount of haemoglobin or the oxygen concentration in the air.
This objective is assessed through structured response, commonly using Explain / Draw.
Explain / Draw
Build the answer around this relationship: Respiring tissues produce carbon dioxide, which lowers blood pH.
Drawing or describing the Bohr shift in the wrong direction when carbon dioxide increases.
Representative question
Explain, with the aid of an annotated diagram, how physical exercise affects the affinity of hemoglobin for oxygen.
a. diagram showing normal oxygen dissociation curve
b. diagram showing curve with increased CO2 to the right
c. both axes correctly labelled
d. where tissues are respiring there is a higher concentration of CO2
e. exercise increases the amount of CO2 in the blood
f. an increase in CO2 lowers the pH of the blood
g. a lower pH causes hemoglobin to release oxygen
h. lower pH decreases hemoglobin affinity for O2 /changes hemoglobin conformation
i. oxygen is released in tissue where it is required for respiration
j. this is known as the Bohr effect/shift
k. at the lungs the low concentration of CO2 means oxygen attaches to hemoglobin
I. «Bohr» effect particularly important during exercise
Apply [4 max] if no diagram.
6 max
An oxygen dissociation curve plots haemoglobin saturation against oxygen partial pressure and shows how readily oxygen binds or is released.
The sigmoidal shape reflects cooperative binding: binding one oxygen changes haemoglobin shape and makes later binding easier. Curve position reveals affinity; a right shift means lower affinity.
Read the graph by checking: partial pressure; saturation; steep unloading region; curve shift.
A right-shifted curve reaches lower saturation at a given oxygen pressure, so it can unload more oxygen in active tissue.
A curve does not show oxygen flow or blood volume by itself; it shows binding relationship under specified conditions.
This objective is assessed through essay response, commonly using Explain / Discuss / State.
Explain / Discuss / State / Identify / Describe
Build the answer around this relationship: Adult haemoglobin shows a sigmoid oxygen dissociation curve because of cooperative binding.
Reversing graph axes or failing to label partial pressure of oxygen and percentage saturation correctly.
Representative question
Discuss the significance of the oxygen dissociation curves for adult hemoglobin and fetal hemoglobin.
a. oxyhemoglobin forms when partial pressure of oxygen is high OR oxyhemoglobin dissociates/breaks apart when partial pressure of oxygen is low
b. respiring tissues have low partial pressure of oxygen
c. sketch/statement of S-shaped «oxygen dissociation» curve
d. axes of graph labelled correctly as percentage oxygen saturation of hemoglobin on y-axis AND partial pressure of oxygen on x-axis
e. «small» decrease in oxygen partial pressure over steep part of curve results in dissociation of oxyhemoglobin/oxygen release to tissues
f. fetal hemoglobin is structurally different from adult/maternal hemoglobin
g. fetal dissociation curve to left of adult dissociation curve
h. fetal hemoglobin has greater affinity for oxygen than adult/maternal blood
i. fetus obtains its oxygen from mother’s blood «at placenta»
j. at any given partial pressure of oxygen fetus will take up oxygen from mother OR
fetal hemoglobin always more saturated with oxygen than maternal blood
Some of these points may be present in annotated diagrams.
Both needed. Do not accept reverse axes.
6 max
Haemoglobin increases oxygen transport because oxygen is poorly soluble in plasma. Reversible and cooperative binding allow loading at high pO2 and unloading at low pO2. High carbon dioxide lowers pH and causes the Bohr shift, reducing affinity and promoting oxygen release in active tissues. Dissociation curves show these changes through sigmoid shape and left/right shifts.