9.1 Electric current

Syllabus
9702–2028–2029
Topic
9.1
Level
AS

Electric current needs moving charge carriers

An electric current is a flow of charge carriers. A particle contributes to current only if it has electric charge and moves so that charge crosses a chosen section; neutral particles such as neutrons cannot carry current.

Medium Mobile charge carriers
metal free electrons
electrolyte positive and negative ions
ionised gas or particle beam ions, electrons or other charged particles
semiconductor electrons and holes

Conventional current is defined in the direction positive charge would move. Positive carriers move with conventional current; negative carriers move in the opposite direction. In a metal wire, electrons drift from the negative terminal towards the positive terminal, opposite to conventional current.

The current magnitude tells how rapidly charge crosses the section: 1 ampere means 1 coulomb per second. A larger number of carriers crossing each second, or a larger charge per carrier, gives a larger current.

Current is not a flow of energy and is not a single electron. Charge carriers drift through the material; energy transfer in the circuit is a related but different process.

Charge is quantised in integer multiples of the elementary charge

Electric charge occurs in discrete amounts q=ne, where n is an integer and e≈1.60×10⁻¹⁹ C.

Use the sign to identify positive or negative carriers and interpret n as a count, not a continuously adjustable fraction.

A charge of −3.2×10⁻¹⁹ C corresponds to two excess electrons.

The quantisation statement does not mean every macroscopic measurement visibly jumps by e; huge carrier counts make charge appear continuous.

Charge transferred by a steady current is Q=It

For constant current, charge transferred in time t is Q=It; for changing current, use the area under an I–t graph.

Use seconds and coulombs, and state whether Q is magnitude or signed charge according to the chosen direction.

A 0.50 A current flowing for 4.0 minutes transfers Q=120 C.

Do not use minutes directly with amperes, and do not assume Q=It for a changing current without integrating or finding graph area.

Count drifting carriers to derive and use I = Anvq

In time t, carriers with average drift speed v travel distance vt. The cylinder that crosses a conductor section of area A has volume Avt, so it contains nAvt carriers. Their total charge magnitude is Q = nAvtq. Dividing by t gives I = Q/t = Anvq.

I=AnvqI = Anvq

Symbol Meaning SI unit
I current magnitude A
A conductor cross-sectional area perpendicular to drift
n number of mobile charge carriers per unit volume m⁻³
v average drift speed m s⁻¹
q magnitude of charge on each carrier C

A wire carries 1.2 A with A = 4.7 × 10⁻⁷ m², n = 8.5 × 10²⁸ m⁻³ and q = 1.60 × 10⁻¹⁹ C. v = I/(Anq) = 1.2/[(4.7 × 10⁻⁷)(8.5 × 10²⁸)(1.60 × 10⁻¹⁹)] = 1.9 × 10⁻⁴ m s⁻¹.

For series sections made of the same material, I, n and q are the same. Therefore v ∝ 1/A: halving wire diameter makes area one quarter as large and drift speed four times larger.

Use cross-sectional area, not diameter: A = πd²/4 for a circular wire. n is a volume number density, not total carriers. Drift speed is usually small and is not the speed at which an electrical signal or energy transfer is established around the circuit.