Use the substitution u=1−sinx to find the exact value of
∫π23π1−sinxsin2xdx
Give your answer in the form a+b2 where a and b are rational numbers to be determined.
State or imply du=−cosxdx Use sin2x=2sinxcosx and write the integral in terms of u
*M1
Obtain ±2∫u(1−u)du or equivalent Integrate correctly to obtain au21+bu23 Obtain correct −4u21+34u23 Correctly use limits u=2 and 0 in an expression of the form au21+bu23 OR limits x=23π and 21π in an expression of the form a(1−sinx)21+b(1−sinx)23 Obtain 38−342