Question 1[Maximum number: 3]Calcium metal reacts with chlorine gas to form calcium chloride, CaCl2\mathrm{CaCl}_{2}CaCl2.Use your answer to (ii) and the following data, together with relevant data from the Data Booklet, to calculate a value for ΔHlatt ⊖\Delta H_{\text {latt }}^{\ominus}ΔHlatt ⊖ for calcium chloride.ΔHlatt ⊖=……………....................kJ mol−1 \Delta H_{\text {latt }}^{\ominus}=\ldots \ldots \ldots \ldots \ldots . . . . . . . . . . . . . . . . . . . . k J ~ m o l-1 ~ΔHlatt ⊖=……………....................kJ mol−1 Mark as masteredShow AnswerΔHlatt θ=−796−242−178−590−1150+(2×349)=−2258 kJ mol−1\Delta \mathrm{H}_{\text {latt }}{ }^{\theta}=-796-242-178-590-1150+(2 \times 349)=-2258 \mathrm{~kJ} \mathrm{~mol}^{-1}ΔHlatt θ=−796−242−178−590−1150+(2×349)=−2258 kJ mol−1Add to Test