3.4 Sound

Syllabus
0625–2026–2027
Topic
3.4
Level

Learning objectives

Explain how a vibrating source produces sound

A sound starts when a source vibrates: it moves repeatedly backwards and forwards about an equilibrium position.

Stage What happens
source an object such as a loudspeaker cone, tuning fork or vocal cord vibrates
nearby medium the source pushes and pulls neighbouring particles
outward transfer each disturbed region affects the next, so the sound disturbance travels away

Touching a sounding tuning fork lightly to water can reveal its vibration by making splashes. Stopping the fork from vibrating stops the sound it produces.

The source must vibrate, but the source itself does not travel to the listener. It transfers a disturbance into the surrounding medium.

Describe why sound waves are longitudinal

A sound wave is longitudinal: particles of the medium vibrate parallel to the direction in which the wave and its energy travel.

Direction In a sound wave
wave travel from the source towards the listener
particle vibration backwards and forwards along the same line

A particle oscillates about its own equilibrium position as the disturbance passes. It transfers energy to neighbouring particles rather than being carried from source to listener.

A graph of sound may be drawn with peaks and troughs, but that drawing does not make sound transverse. Classify the wave by the direction of particle vibration relative to wave travel.

Use the human audible-frequency range

A healthy human with normal hearing can hear approximately 20 Hz to 20 000 Hz. The upper value is also written as 20 kHz.

Frequency Relative to the approximate human range
below 20 Hz below the audible range
20 Hz to 20 000 Hz audible range
above 20 000 Hz above the audible range

Convert before comparing: 1 kHz = 1000 Hz, so 15 kHz = 15 000 Hz and lies inside the approximate range.

The limits are approximate and vary between people and with age. A sound outside the human range may still be detected by another animal or by equipment.

Explain why sound needs a medium

Sound is a mechanical wave, so it needs a material medium to transmit its disturbance.

Region Can sound be transmitted? Reason
solid, liquid or gas yes particles can interact and pass on the vibration
vacuum no there are no particles to pass on the vibration

An astronaut outside a spacecraft cannot hear machinery through the vacuum between them, even if the machinery is loud and its frequency is in the human audible range.

A vacuum does not merely make sound quieter: it prevents sound transmission. Electromagnetic waves such as light can cross a vacuum, but sound cannot.

Use the approximate speed of sound in air

The speed of sound in air is approximately 330–350 m/s; 340 m/s is a useful typical value.

Statement Meaning
340 m/s sound travels about 340 m through air in 1 s
0.34 km/s the same typical speed expressed in kilometres per second

For one-way travel, use speed = distance ÷ time. A sound that travels 680 m through air in 2.0 s has speed 680 ÷ 2.0 = 340 m/s.

Do not use 3.0 × 10^8 m/s: that is the speed of electromagnetic waves in a vacuum. The sound value is approximate, so a value within 330–350 m/s may be appropriate.

Measure the speed of sound using distance and time

Choose a long, measured distance between a sound source and one observer. A starting pistol is useful because its puff of smoke and bang are produced together.

Step Measurement action
1 measure the source-to-observer distance with a long tape or trundle wheel
2 the observer starts the stopwatch on seeing the smoke
3 the same observer stops the stopwatch on hearing the bang
4 calculate speed = measured distance ÷ measured time

Use a long distance so the sound delay is much larger than the timing resolution. Repeat the measurement and average the times; keep the source and observer positions fixed.

The light-travel time is negligible over this distance, so the smoke gives the start time. Do not double the measured distance in this direct one-way method; doubling applies to an echo that travels out and back.

Relate amplitude and frequency to loudness and pitch

Amplitude controls loudness, while frequency controls pitch.

Wave change Heard effect
greater amplitude louder sound
smaller amplitude quieter sound
greater frequency higher pitch
smaller frequency lower pitch

The two properties can change independently: a note can become louder at the same pitch, or higher-pitched at the same loudness.

Do not use amplitude to rank pitch or frequency to rank loudness. A high-pitched sound is not necessarily loud, and a loud sound is not necessarily high-pitched.

Describe an echo as reflected sound

An echo is a sound heard after a sound wave reflects from a surface and returns to the listener or detector.

Stage Path
outward source → reflecting surface
return reflecting surface → receiver
measured delay time for both outward and return journeys

If the receiver is beside the source, distance to the reflector = speed × echo time ÷ 2. At 330 m/s, an echo after 0.60 s comes from a surface about 99 m away.

Reflection changes the direction of the sound path. The measured echo time is round-trip time, so using speed × time without dividing by 2 gives twice the distance to the surface.

Define ultrasound using the 20 kHz boundary

Ultrasound is sound with a frequency higher than 20 kHz, which is higher than 20 000 Hz.

Sound Frequency condition Human with normal hearing
audible sound approximately 20 Hz to 20 kHz normally audible
ultrasound greater than 20 kHz not audible

Ultrasound is still a sound wave: it is longitudinal and needs a material medium. Its name describes frequency, not a different type of wave motion.

The definition is frequency greater than 20 kHz, not great loudness, small amplitude or high speed. A value exactly at 20 kHz is the approximate upper hearing boundary, not higher than it.

Describe compressions and rarefactions

A longitudinal sound wave consists of alternating compressions and rarefactions in the medium.

Region Particle spacing Density and pressure
compression particles closer together than normal higher density and pressure
rarefaction particles farther apart than normal lower density and pressure

One wavelength is the distance from the centre of one compression to the centre of the next compression, or from one rarefaction centre to the next.

Compressions are not individual particles moving all the way through the medium. The pattern travels while each particle vibrates backwards and forwards about its own equilibrium position.

Compare the speed of sound in solids, liquids and gases

In general, sound travels fastest in solids, more slowly in liquids and slowest in gases.

State General relative speed Typical scale
gas slowest air about 340 m/s
liquid faster water about 1500 m/s
solid fastest many solids: several thousand m/s

For equal path lengths, the sound travelling through the solid generally arrives first, followed by the liquid path and then the gas path.

This is a general order, not a claim that every solid has one fixed speed or that density alone determines speed. Always use a supplied material value when a calculation provides one.

Explain ultrasound uses and calculate echo distance

Ultrasound pulses can travel through a material and reflect at a boundary. The returning echo reveals where a boundary, flaw or object is located.

Use How ultrasound provides information
non-destructive testing echoes from cracks, bubbles or internal boundaries locate defects without cutting open the material
medical scanning of soft tissue different tissue boundaries return echoes that are processed into an image
sonar echoes from the seabed or an underwater object give depth or distance

For a pulse that returns to its source, depth or distance = wave speed × total echo time ÷ 2. In seawater at 1500 m/s, a return time of 0.080 s gives 1500 × 0.080 ÷ 2 = 60 m.

Use the wave speed in the actual medium and convert time to seconds. The factor of 2 is required because the measured time includes the outward and return journeys.