5. Nuclear physics

Syllabus
0625–2026–2027
Section
5
Level
—

5.1.1 The atom

Syllabus
0625–2026–2027
Topic
5.1.1
Level
—

Describe the nuclear model of an atom

An atom has a very small, positively charged nucleus at its centre. Negatively charged electrons orbit around the nucleus. The nucleus and electrons occupy different regions of the atom.

Region or particle Location Charge
nucleus tiny central region positive
electrons outside and orbiting the nucleus negative
space between most of the atom's volume no material filling it continuously

A neutral atom has equal total positive and negative charge. Its nucleus is still positive and its electrons are still negative; neutral describes the combined charge of the whole atom.

Diagrams are models and are not drawn to scale. The nucleus is much smaller than the atom, while the electron region accounts for the atom's overall size.

Do not place electrons inside the nucleus or describe the nucleus as neutral. The detailed proton-and-neutron composition of the nucleus is a separate next objective.

Form positive and negative ions

An ion forms when an atom gains or loses electrons. The nucleus does not gain or lose positive charge during this process.

Electron change Result Why
atom loses one electron 1+ ion one more unit of positive than negative charge
atom loses two electrons 2+ ion two more units of positive than negative charge
atom gains one electron 1− ion one more unit of negative than positive charge
atom gains two electrons 2− ion two more units of negative than positive charge

Lose negative electrons → become positive. Gain negative electrons → become negative. The sign follows the imbalance left after the electron transfer.

A magnesium atom that loses two electrons forms Mg²⁺. A chlorine atom that gains one electron forms Cl⁻.

Ordinary ion formation changes the number of electrons, not the nucleus. Removing a proton is not how a positive ion forms, and adding positive charge to the nucleus is not required.

Infer the atom from alpha scattering

In the alpha-scattering experiment, a narrow beam of positively charged alpha particles is directed at a very thin metal foil. Detectors record whether each particle passes through or changes direction.

Observation Conclusion about the atom Reasoning
most alpha particles pass straight through the atom is mostly empty space most particles meet no concentrated matter or charge
some alpha particles are deflected positive charge is concentrated in the nucleus positive alpha particles are repelled by positive nuclear charge
only a very small fraction are deflected through large angles or backwards the nucleus is very small very few particles pass close enough for a strong interaction
a few alpha particles reverse or change direction sharply the nucleus contains most of the atom's mass the massive nucleus remains almost stationary while the alpha particle changes momentum

An alpha particle passing far from a nucleus is nearly undeflected. Passing closer produces stronger repulsion and a larger bend. A near head-on approach can send it back along or near its incoming path.

Together, the results support a nuclear atom: a tiny positively charged nucleus containing most of the mass, surrounded by mostly empty space.

The scattering evidence does not by itself show that the nucleus contains protons and neutrons. Match each observation only to the size, charge, mass concentration or empty-space conclusion it supports.

5.1.2 The nucleus

Syllabus
0625–2026–2027
Topic
5.1.2
Level
—

Identify what is inside a nucleus

The nucleus of an atom is made of protons and neutrons. Together, protons and neutrons are called nucleons.

Particle Location Role in the nucleus
proton inside the nucleus nucleon that contributes positive charge and mass
neutron inside the nucleus uncharged nucleon that contributes mass
electron outside the nucleus not part of the nucleus

A nucleus contains protons and neutrons, not electrons. The number of protons and neutrons need not be equal.

Recall the relative charges of particles

Particle Relative charge
proton +1
neutron 0
electron −1

A proton and an electron have equal charge magnitude but opposite signs. A neutron is uncharged; it is not a negatively charged particle.

The charge of a collection of particles is the sum of their relative charges. Protons add positive charge, electrons add negative charge and neutrons add none.

Relative charge has no unit and does not state particle mass. Keep charge and mass comparisons separate.

Use proton number and nucleon number

Quantity Symbol Meaning
proton number (atomic number) Z number of protons in the nucleus
nucleon number (mass number) A total number of protons and neutrons in the nucleus
neutron number — A − Z

Read Z to get the number of protons. Subtract Z from A to get neutrons. For a neutral atom only, the number of electrons equals Z.

For chlorine-35 with Z = 17: protons = 17, neutrons = 35 − 17 = 18, and a neutral atom has 17 electrons.

A is not the neutron number. Do not subtract in the opposite direction, and do not assume an ion has Z electrons.

Read and write nuclide notation

Nuclide notation is written with the nucleon number A at the upper left and proton number Z at the lower left of the element symbol X: ᴬ_ZX.

Part Position Meaning
A upper left protons + neutrons
Z lower left protons and element identity
X centre/right chemical symbol of the element

A platinum nucleus with 78 protons and 118 neutrons has A = 196 and is written ¹⁹⁶₇₈Pt.

Check that A is at least Z and that A − Z gives a whole, non-negative neutron number. The element symbol must match Z.

Recognise isotopes of one element

Isotopes are atoms of the same element with the same number of protons but different numbers of neutrons. An element may have more than one isotope.

Feature Isotopes of the same element
proton number Z same
number of protons same
number of neutrons different
nucleon number A different
element symbol same

Carbon-12 and carbon-14 both have Z = 6, so both contain 6 protons. Carbon-14 has two more neutrons and a greater nucleon number.

Isotopes are not required to be radioactive or unstable. Different proton numbers mean different elements, not isotopes of one element.

Compare nuclear fission and fusion

Process Nuclear change Typical setting
fission a heavy nucleus splits into two or more smaller nuclei, often after absorbing a neutron; neutrons may be released nuclear reactor
fusion two light nuclei join to form a heavier nucleus; very high temperature helps them overcome electrostatic repulsion stars

Both processes can release energy. In each energy-releasing reaction, the total mass of the products is slightly smaller than the total mass before the reaction; the mass decrease corresponds to released energy.

In a nuclide equation, balance both totals across the arrow: upper nucleon numbers must sum to the same value on both sides, and lower proton numbers must also sum to the same value.

Fission pattern: ¹₀n + ²³⁵₉₂U → two smaller nuclei + further ¹₀n particles + energy. The exact product nuclei can vary, but both number sums must balance.

Fusion example: ²₁H + ³₁H → ⁴₂He + ¹₀n + energy. Upper numbers balance 5 = 4 + 1 and lower numbers balance 2 = 2 + 0.

Fission is nuclear splitting and fusion is nuclear joining; neither is electron transfer or a chemical reaction. Released energy does not mean nucleon or proton totals fail to balance.

Relate proton number to nuclear charge

A nucleus contains Z protons and each proton has relative charge +1. Neutrons have charge 0, so the relative charge of the nucleus is +Z.

Proton number Z Relative nuclear charge
1 +1
6 +6
79 +79

For a neutral atom, Z electrons outside the nucleus supply total charge −Z and balance the nuclear charge +Z.

Nuclear charge depends on proton number, not nucleon number. Neutrons increase mass but do not increase charge.

Relate nucleon number to nuclear mass

Protons and neutrons each have relative mass approximately 1, while electron mass is negligible at this scale. A nucleus with nucleon number A therefore has relative mass approximately A.

Quantity Nuclear relationship
number of protons + neutrons A
relative nuclear mass approximately A
relative nuclear charge +Z, not +A

A helium-3 nucleus has relative mass about 3; a helium-4 nucleus has relative mass about 4. Their charge is the same because both have Z = 2.

A is a particle count and an approximate relative mass, not a mass in kilograms. It does not give nuclear charge or electron number.

5.2.1 Detection of radioactivity

Syllabus
0625–2026–2027
Topic
5.2.1
Level
—

Define background radiation

Background radiation is ionising radiation that is always present in the environment, including when no deliberately placed radioactive source is nearby.

A detector can therefore record counts before an experimental source is introduced or after it is removed. This persistent reading is a real environmental contribution, not automatically a detector zero error.

The measured background level depends on the place, surroundings and measuring interval, so it should be measured for the experiment rather than assumed to be zero.

Background radiation names the radiation already present, not the reading produced by the source under investigation.

Identify sources of background radiation

Significant source Where it comes from
radon gas radioactive gas in the air, often entering from the ground
rocks and buildings radioactive materials in the ground and construction materials
food and drink naturally occurring radioactive isotopes taken into the body
cosmic rays high-energy radiation arriving from space

A complete syllabus list includes all four: radon gas in air; rocks and buildings; food and drink; and cosmic rays.

Radon and rocks/buildings are terrestrial sources, food and drink contribute internally after intake, and cosmic rays come from beyond Earth.

Ordinary seismic waves are not ionising radiation and do not contribute to the background count. Do not replace the required source with a vague phrase such as 'the environment'.

Measure ionising radiation with a detector and counter

Component Function
radiation detector responds when ionising radiation reaches its sensitive region
counter records the detector pulses as a number of counts
timer defines the measurement interval so a count rate can be calculated

Place the detector in the required position, connect it to the counter, measure for a known time and record the counts. Repeating a measurement can provide a more stable average.

A count is one registered detection event. The detector-counter reading does not necessarily equal the number of particles emitted by the source because not every emission reaches or is registered by the detector.

A detector connected to a counter measures counts; it does not by itself identify the radiation type, energy or source activity without additional method and interpretation.

Express a count rate

Count rate is the number of registered counts divided by the measurement time: count rate = number of counts ÷ time.

Time unit used Count-rate unit
seconds counts/s
minutes counts/minute

If 360 counts are recorded in 3 minutes, the count rate is 360 ÷ 3 = 120 counts/minute. In seconds, 3 minutes is 180 s, so the same result is 2 counts/s.

Keep the count and time interval together. To compare rates, first express both using the same time unit; 60 counts/minute equals 1 count/s.

Counts and count rate are different quantities. A total of 300 counts is not 300 counts/s unless the measurement lasted exactly 1 second.

Calculate a corrected count rate

The detector reading with a source contains both source radiation and background radiation. Correct it using: corrected source count rate = measured count rate with source − background count rate.

Step Action
1 measure background with the source absent, using the same detector position and a known time
2 repeat and average background measurements when data are provided
3 convert background counts to a rate using counts ÷ time
4 measure the total rate with the source present in the same unit
5 subtract the background rate from the total rate

Background counts of 170, 164 and 185 in separate 10-minute intervals average to 173 counts in 10 minutes, or 17.3 counts/minute. If the total rate with the source is 949 counts/minute, the corrected rate is 949 − 17.3 ≈ 932 counts/minute.

A corrected decay curve lies below the uncorrected curve by the background rate. An uncorrected curve approaches the background level; a correctly background-subtracted curve approaches zero.

Subtract rates from rates, not a raw count from a rate. Background is removed once only; do not add it or halve the total before subtracting it.

5.2.2 The three types of nuclear emission

Syllabus
0625–2026–2027
Topic
5.2.2
Level
—

Understand spontaneous and random nuclear emission

Radiation emission from an unstable nucleus is spontaneous: it happens without being started by heating, pressure, a chemical reaction or another external trigger.

The emission is random. The exact nucleus that will emit next and the exact time of its emission cannot be predicted, so repeated detector readings naturally fluctuate.

The direction is also random. Emissions from many nuclei leave in different directions rather than following one preferred direction.

Although one event is unpredictable, a large sample can show a stable statistical pattern when counts are collected over suitable time intervals.

Random variation does not by itself mean the detector is faulty, and spontaneous does not mean that every nucleus emits at once or at a constant individual schedule.

Compare alpha, beta and gamma emissions

Emission Nature and charge Relative ionising effect Relative penetration and typical absorber
alpha (α) helium nucleus: 2 protons + 2 neutrons; charge +2 greatest least; stopped by paper or a few centimetres of air
beta (β−) fast electron emitted from the nucleus; charge −1 intermediate intermediate; stopped by a few millimetres of aluminium
gamma (γ) electromagnetic radiation; no charge and no rest mass least greatest; reduced by thick lead or concrete

In this syllabus, beta means β− only. β+ emission is explicitly outside scope.

The radiation that ionises most strongly loses energy most rapidly in matter, so it travels the shortest distance and has the lowest penetrating ability. Gamma interacts less frequently and is therefore the most penetrating.

Penetrating ability is not the same as speed. Gamma is most penetrating because it interacts less readily with matter, not because 'more penetrating' simply means 'faster'.

Predict deflection in electric and magnetic fields

Emission Charge Behaviour in an electric field
α +2 bends towards the negative plate
β− −1 bends towards the positive plate, usually much more strongly than α
γ 0 remains undeflected

An electric field exerts forces in opposite directions on positive and negative charges. Beta bends more because its mass is far smaller than the mass of an alpha particle.

Emission Behaviour in a magnetic field
α and β− bend in opposite directions because their charges have opposite signs
γ remains undeflected because it is uncharged

For a magnetic-field diagram, use the beam direction, field direction and the force rule for a positive charge; reverse that force direction for β−. The beta path normally has the tighter curvature because beta has much smaller mass.

Identify whether the diagram shows an electric or magnetic field before predicting a path. A charged emission is deflected in both; gamma is undeflected in both.

Explain relative ionising effects

Ionisation occurs when an interaction removes an electron from an atom or molecule, leaving an ion.

A larger electric charge produces a stronger electrical interaction with electrons in nearby atoms. An alpha particle has charge +2, so it interacts more strongly than a beta particle with charge −1; gamma has no charge and interacts less frequently.

Kinetic energy is transferred during interactions that cause ionisation. For the same kinetic energy, the much more massive alpha particle travels more slowly than a beta particle, remains near atoms for longer and produces dense ionisation along a short path.

Emission Charge/interaction pattern Relative ionising effect
α +2; strong, frequent interactions and dense energy transfer greatest
β− −1; weaker charged-particle interactions intermediate
γ uncharged; less frequent interactions least

Do not explain the ranking using penetration alone. Greater ionisation causes faster energy loss and therefore lower penetration; it is the charge and transfer of kinetic energy in interactions that provide the explanation.

5.2.3 Radioactive decay

Syllabus
0625–2026–2027
Topic
5.2.3
Level
—

Define radioactive decay

Radioactive decay is a change in an unstable nucleus that can result in the emission of an alpha particle, a beta-minus particle and/or gamma radiation.

The change is spontaneous: it occurs without an external trigger. Heating, cooling, pressure and chemical reactions do not select when a nucleus decays.

The change is random: it is impossible to predict which particular nucleus will decay next or the exact time at which it will decay.

For a large sample, the behaviour of many nuclei can form a statistical pattern even though each individual event remains unpredictable.

A lead container may absorb emitted radiation, but it does not stop the nuclei inside from decaying. Random detector readings are therefore expected, not proof that the detector is faulty.

Relate alpha and beta decay to a new element

An element is identified by its proton number. If a decay changes the number of protons in the nucleus, the product nucleus belongs to a different element.

Decay Change in proton number Result
alpha decreases by 2 a nucleus of a different element
beta-minus increases by 1 a nucleus of a different element

Alpha emission removes two protons as part of the alpha particle. In beta-minus decay, a neutron changes into a proton and an electron, and the electron is emitted, so the nucleus gains one proton.

The daughter can be an isotope, but it is an isotope of the new element, not another isotope of the original element. Gamma emission alone does not change proton number and therefore does not change the element.

Explain why some isotopes are radioactive

An isotope may be radioactive because its nucleus is unstable. Two syllabus reasons are an excess of neutrons and a nucleus that is too heavy.

Isotopes of one element have the same proton number but different neutron numbers. An isotope with too many neutrons for a stable arrangement can reduce that neutron excess through radioactive change.

A very heavy nucleus contains a large total number of nucleons. The balance of forces can be unstable, so the nucleus may emit radiation and move towards a more stable arrangement.

Do not infer that every isotope with more neutrons is radioactive or that physical size alone determines stability. The required statements are that neutron excess and/or excessive nuclear mass may cause instability.

Describe how each emission changes the nucleus

Emission Change inside or from nucleus Change in A Change in Z
alpha 2 protons and 2 neutrons leave −4 −2
beta-minus neutron → proton + electron; electron leaves 0 +1
gamma nucleus loses energy as electromagnetic radiation 0 0

Radioactive emission moves an unstable nucleus towards greater stability. Alpha emission removes two neutrons as well as two protons; beta-minus emission converts one excess neutron into a proton; gamma emission removes excess nuclear energy without changing the numbers of protons or neutrons.

The electron emitted in beta-minus decay is created by the nuclear change; it is not an orbital electron. Nucleon number stays constant because one nucleon changes type.

Gamma emission can increase stability without reducing the neutron number. Alpha and beta-minus change the element; gamma alone does not.

Write and balance nuclear decay equations

Write a nuclide as ᴬ_ZX, where A is the nucleon number and Z is the proton number. In every decay equation, the totals of A and Z must balance on both sides.

Emission Emitted term Daughter change
alpha ⁴₂He (or ⁴₂α) A − 4, Z − 2
beta-minus ⁰₋₁e (or ⁰₋₁β) A unchanged, Z + 1
gamma ⁰₀γ A unchanged, Z unchanged

Alpha example: ²³⁸₉₂U → ²³⁴₉₀Th + ⁴₂He. Both nucleon numbers balance, 238 = 234 + 4, and both proton numbers balance, 92 = 90 + 2.

Beta-minus example: ¹⁴₆C → ¹⁴₇N + ⁰₋₁e. The nucleon number remains 14 and the proton-number total balances because 6 = 7 + (−1).

Gamma example: ᴬ_ZX* → ᴬ_ZX + ⁰₀γ. The asterisk indicates a higher-energy nucleus; emission changes neither A nor Z.

Method: identify the emission, write its A and Z values, conserve both columns, then use the daughter proton number to identify the new element.

For beta-minus decay, do not subtract one from the daughter proton number: the daughter has one more proton. For gamma emission, do not invent a new element because both numbers are unchanged.

5.2.4 Half-life

Syllabus
0625–2026–2027
Topic
5.2.4
Level
—

Define and use half-life

The half-life of a particular isotope is the time taken for half the radioactive nuclei in any sample of that isotope to decay.

Because activity and corrected count rate are proportional to the number of undecayed nuclei, each also halves in one half-life when the same measurement arrangement is used.

Number of half-lives Fraction remaining Fraction decayed
0 1 0
1 1/2 1/2
2 1/4 3/4
3 1/8 7/8

For an elapsed time t and half-life T, first find the number of half-lives n = t ÷ T, then halve the starting number, mass, activity or corrected count rate n times. The amount decayed equals initial amount minus amount remaining.

A source has a half-life of 5 days and an initial mass of 400 mg. After 10 days, two half-lives have passed: 400 → 200 → 100 mg, so 100 mg remains and 300 mg has decayed.

The sample does not become zero after one or two half-lives. For the simple calculations in this objective, use source-only or corrected values: background radiation is excluded.

Find half-life when background is included

An uncorrected detector reading M contains source count rate S and background count rate B: M = S + B. Only S halves; B is treated as constant.

Step From raw data or a curve
1 identify B from the stated background or the late-time plateau
2 at time t₁, calculate source rate S₁ = M₁ − B
3 calculate the half-source target S₂ = S₁/2
4 convert back to a detector reading M₂ = S₂ + B
5 read the time t₂ at M₂; half-life = t₂ − t₁

Equivalently, the detector reading after one half-life is B + (M₁ − B)/2 = (M₁ + B)/2. It is not usually M₁/2.

If the measured rate starts at 100 counts/min and background is 20 counts/min, the source rate is 80. After one half-life it is 40, so the detector reads 40 + 20 = 60 counts/min. The time for the curve to fall from 100 to 60 is one half-life.

Use more than one halving interval when the data allow it. Similar intervals support the estimate; small differences are expected because radioactive counts fluctuate randomly and graph readings have uncertainty.

Do not halve the background and do not subtract it twice. An uncorrected decay curve approaches the background level, not zero.

Choose isotopes for practical applications

Choose both the radiation type and the half-life. The radiation must penetrate or be absorbed by the intended amount of material, and the half-life must keep the source useful for long enough without causing unnecessary prolonged exposure or replacement.

Application Suitable radiation and why Suitable half-life and why
household smoke alarm alpha: strongly ionises air, short range, and smoke absorption changes the current long: reliable for many years with little replacement
irradiating food to kill bacteria gamma: penetrates food and packaging and kills microorganisms long enough for repeated practical use and stable output
sterilising equipment gamma: penetrates equipment and packaging and destroys microorganisms long enough for an industrial source to remain useful
measuring/controlling thin material beta for paper or thin aluminium: partly absorbed, so detector rate changes with thickness long: output stays usable and the source is not replaced often
cancer diagnosis gamma: escapes the body for external detection and is weakly ionising short enough to reduce dose, but long enough to complete the procedure
cancer treatment gamma: penetrates tissue and can destroy cancer cells chosen to provide a controllable useful treatment source without unnecessary persistence

For thickness control, alpha would be absorbed by even a very thin sheet, while gamma may pass through with too little change. Beta gives a measurable change in detector count when thickness changes.

A diagnostic tracer must not decay before it reaches the target and measurements are completed, but should decay soon afterwards. Treatment and sterilisation require sufficient penetration and dose, so the source arrangement and service life also matter.

There is no universal rule that every application needs the shortest or longest half-life. State why the chosen duration fits the actual operating time and exposure risk.

5.2.5 Safety precautions

Syllabus
0625–2026–2027
Topic
5.2.5
Level
—

Describe the effects of ionising radiation

Ionising nuclear radiation can remove electrons from atoms and molecules in living tissue. The resulting ions and chemical changes can damage cells.

Effect What it means
cell death damage is severe enough that a cell can no longer function or reproduce
mutation radiation changes genetic material in a surviving cell
cancer a mutation may disrupt control of cell division, allowing uncontrolled growth

Greater exposure increases the chance and extent of biological damage because more ionising interactions can occur in living tissue.

A mutation does not automatically become cancer, and not every exposed cell dies. The required point is that ionising radiation can cause cell death, mutations and cancer.

Move, use and store radioactive materials safely

Stage Safe practice
move keep the source in a closed shielded container; use an approved carrier or remote handling method
use remove only when needed; handle with tongs or a manipulator; never touch; keep it directed away from people and return it promptly
store place in a suitable shielded, labelled container inside a secure locked store with controlled access

Use the smallest suitable source, restrict use to trained people, monitor personal exposure when required and follow a documented procedure for loss, damage or contamination.

A sealed source keeps radioactive material contained, but its radiation can still leave the source. It therefore still needs time, distance and shielding controls.

A fume cupboard, ordinary glass bottle or high shelf is not automatically safe storage. The source must be shielded against its radiation and secured against unauthorised access.

Explain time, distance and shielding precautions

Precaution How it reduces dose to living tissue
reduce exposure time less time exposed means fewer emissions can reach and ionise tissue
increase distance radiation spreads out, so less reaches a given area of tissue farther from the source
use shielding suitable material between source and tissue absorbs radiation before it reaches the person

Prepare the procedure before exposing the source, use tongs to increase distance, work behind a barrier and return the source to its shielded container immediately after use.

Shielding must match the radiation and be thick enough: paper can stop alpha, aluminium can stop beta, while penetrating gamma generally needs thick lead or concrete.

These principles apply to all ionising radiation. A low-penetration source can still be hazardous at close range or if radioactive material enters the body.

Lead does not repel radiation and does not change a source's half-life. It protects by absorbing radiation; time and distance remain important even when shielding is present.