2.1.3 Gases and the absolute scale of temperature
- Syllabus
- 0625–2026–2027
- Topic
- 2.1.3
- Level
- —
For a fixed mass of gas, pressure changes when particle speed changes or when the same particles collide with the walls more or less frequently.
| Controlled change | Particle account | Pressure effect |
|---|---|---|
| temperature increases at constant volume | particles gain average kinetic energy, move faster, and make more frequent and harder collisions with the same walls | pressure increases |
| temperature decreases at constant volume | particles move more slowly, so collisions are less frequent and less forceful | pressure decreases |
| volume decreases at constant temperature | average speed stays the same, but particles cross a shorter distance and hit each unit area of wall more frequently | pressure increases |
| volume increases at constant temperature | average speed stays the same, but collisions with each unit area of wall become less frequent | pressure decreases |
Name the control before predicting the pressure. Constant volume isolates the effect of temperature on particle speed. Constant temperature isolates the effect of volume on collision frequency; the particles do not speed up merely because the gas is compressed slowly.
These comparisons require the same fixed mass of gas. If gas leaks in or out, or if temperature and volume both change, one simple comparison is not enough to predict the result without further information.
The kelvin and Celsius scales have equal-sized intervals but different zero points: 0 K corresponds to −273 °C.
T(K)=θ(∘C)+273
To convert °C to K, add 273. To convert K to °C, rearrange to θ=T−273.
Examples: 25∘C=25+273=298K. For nitrogen at 77K, θ=77−273=−196∘C.
Write K, not °K: kelvin has no degree sign. A temperature can be negative on the Celsius scale while remaining positive in kelvin; for example, −196 °C is 77 K.
For a fixed mass of gas at constant temperature, pressure and volume are inversely proportional: increasing one decreases the other so that their product stays constant.
pV=constantsop1V1=p2V2
A gas at 120kPa occupies 50cm3 and is compressed at constant temperature to 30cm3. Then p2=(120×50)/30=200kPa. The pressure rises because the volume falls.
On a graph of p against V, the relationship is a decreasing curved line: doubling V halves p, and halving V doubles p. The curve becomes less steep as volume increases and does not meet either axis. A graph of p against 1/V is a straight line through the origin.
Use one consistent volume unit on both sides and one consistent pressure unit on both sides; matching units cancel in the ratio. Do not use pV=constant if the gas mass or temperature changes.