B.2.2—Emissivity

Syllabus
First assessment 2025
Objective
Level
SL

Interpret and Calculate Emissivity

Emissivity

Emissivity, ε\varepsilon, compares the power radiated per unit area by a real surface with that radiated per unit area by an ideal black surface at the same absolute temperature:

ε=P/AσT4\varepsilon=\frac{P/A}{\sigma T^4}

Use the radiation equation

For a surface of area A,

P=εσAT4P=\varepsilon\sigma AT^4

Use T in kelvin. A black body has ε=1\varepsilon=1; real surfaces have emissivity less than or equal to 1 in this model.

What emissivity is not

Emissivity is not the fraction of incoming sunlight reflected; that is albedo. Emissivity concerns emission of thermal radiation by a surface at its temperature.

Worked example from the mapped local textbook

A planet has surface temperature 63C=210K-63\,^{\circ}\mathrm{C}=210\,\mathrm{K}, area 1.4×1014m21.4\times10^{14}\,\mathrm{m^2} and luminosity 1.3×1016W1.3\times10^{16}\,\mathrm{W}.

ε=P/AσT4=(1.3×1016)/(1.4×1014)(5.67×108)(210)4=0.84\varepsilon=\frac{P/A}{\sigma T^4}=\frac{(1.3\times10^{16})/(1.4\times10^{14})}{(5.67\times10^{-8})(210)^4}=0.84

Emissivity is dimensionless, and the kelvin conversion is required by the fourth-power law.

Calculation boundary

Keep surface emission and atmospheric re-radiation as separate energy-flow terms. Do not subtract reflected solar power from the Stefan–Boltzmann emission formula.

B.2.2 Exam Analysis

Assessment in practice

1–3 marks
How it is assessed

The evidence asks students to compare emissivity for regions with equal surface temperature and to calculate atmospheric re-radiation from surface emission and outgoing intensity.

Command terms

Determine / Compare

What earns marks

Use emissivity as a ratio of radiated power per unit area to σT⁴ at the same temperature. For a surface, write P=εσAT⁴, use kelvin, and separate emitted surface power from radiation re-radiated by the atmosphere.

Watch for

Confusing emissivity with albedo or omitting the absolute-temperature requirement in σT⁴.

Representative question

Question 1

[Maximum number: 3]

Determine the average intensity re-radiated by the atmosphere towards the surface. Assume that the emissivity of the surface is 0.90 .

Synthesize B.2 Greenhouse Effect

Start with the energy balance

For a planet at steady average temperature, absorbed incoming radiant power equals emitted outgoing radiant power. Albedo controls the reflected fraction; emissivity controls thermal emission relative to a black body.

Average incoming solar energy

The solar constant S is an intensity on a surface perpendicular to the rays. A spherical planet averages the intercepted power over four times the projected area, giving S/4S/4; with albedo a, the simple globally averaged absorbed intensity is (1a)S/4(1-a)S/4.

Atmospheric mechanism

Earth emits infrared radiation. Greenhouse molecules absorb selected wavelengths through molecular resonance or energy-level transitions, then re-emit in all directions, including back toward the surface.

Human enhancement

The natural greenhouse effect supports a habitable surface temperature. Human-driven increases in greenhouse-gas concentration augment the effect; fossil-fuel burning is a primary cause of this enhanced greenhouse effect.