B.1.14—Black-body radiation
- Syllabus
- First assessment 2025
- Objective
- —
- Level
- SL
Black-body emission
A black body is an ideal surface that emits electromagnetic radiation according to its absolute temperature. Its total emitted power, or luminosity, is modelled by
L=σAT4
Read the variables
A is the emitting surface area, T is absolute temperature in kelvin and σ is the Stefan–Boltzmann constant. The equation gives total power emitted, not the brightness received by a particular observer.
Use proportional reasoning
At fixed area, doubling T multiplies L by 24=16. At fixed temperature, doubling the emitting area doubles L. The fourth-power dependence makes temperature especially important.
Worked comparison from local Question Bank row 29005
Treat Mars at 200K and Earth at 300K as black bodies. For equal emitting area,
LEarthLMars=(300200)4=0.198≈0.20
Mars emits about one fifth as much power per unit area in this ideal model.
Common trap
Do not use Celsius in the fourth-power term, and do not confuse luminosity with apparent brightness, which also depends on distance.
The evidence tests the fourth-power exponent through a line-of-best-fit gradient and tests how surface temperature varies with received intensity.
Explain / Determine
Start with $L=\sigma AT^4$ and identify which quantities are fixed. For a log plot, rewrite as $\ln L=4\ln T+\ln(\sigma A)$ so the gradient with respect to ln T is 4. For graph questions, use the fourth-power dependence: at fixed area, emitted power rises strongly with absolute temperature.
Using Celsius in the fourth-power relation or treating luminosity as proportional to T rather than T⁴.
Representative question
Explain how the gradient of the line of best fit relates to the Stefan-Boltzmann law.
manipulates SB law using logs
relates 4 from SB to 3.99 in the equation of line of best fit as the
same