A.3.13—Efficiency
- Syllabus
- First assessment 2025
- Objective
- —
- Level
- SL
Useful fraction
Efficiency is the ratio of useful output to total input:
η=EinputEuseful=PinputPuseful
Choose matching quantities
Use energy ratios for the same process and time interval, or power ratios when input and output are rates. Efficiency is dimensionless and is often reported as a percentage.
Worked example from local Question Bank row 29709
Solar intensity is 240Wm−2 over 2.50×104m2, so input power is
Pin=(240)(2.50×104)=6.0×106W=6.0MW
For a useful output of 1.6MW,
η=6.01.6=0.27=27%
The remaining input is transferred through non-useful pathways.
Common trap
Do not invert the ratio or use the total output, including unwanted transfers, as the useful output.
The evidence asks for motor input power from output power and efficiency, and for fuel mass or energy from a vehicle’s kinetic-energy gain and efficiency.
Calculate / Identify
Use the useful-output/input ratio and convert the final fraction to a percentage when required. For a motor, calculate useful mechanical output first, then divide by electrical input power.
Using the loss power as useful output or reporting 75 rather than 0.75 when using the ratio.
Representative question
An electric motor of efficiency 75 % raises a mass of 120 kg at a constant speed of 0.50 ms−1. What is the power input to the motor?
20 W
450 W
600 W
800 W
D