A.3.10—Gravitational potential energy
- Syllabus
- First assessment 2025
- Objective
- —
- Level
- SL
Near-Earth gravitational potential energy
For a height change Δh in a uniform gravitational field,
ΔEp,g=mgΔh
Use the height change
Raising an object gives positive change in gravitational potential energy; lowering it gives negative change relative to the chosen reference.
Link to power
If height changes at constant speed, the rate of gravitational potential-energy gain is mgv, before accounting for efficiency or other transfers.
Worked example from local Question Bank row 37039
An object's weight is 6.10×102N and it rises vertically by 8.0m. Since mg is its weight,
ΔEp,g=(6.10×102)(8.0)=4.88×103J≈4.9kJ
The positive result means the gravitational potential-energy store increases.
Common trap
Use the local value of g and the vertical height change, not the distance along a slope.
[ 1 ]
A car takes 20 minutes to climb a hill at constant speed. The mass of the car is 1200 kg and the car gains gravitational potential energy at a rate of 6.0 kW . Take the acceleration of gravity to be 10 m s−2. What is the height of the hill?
Account for energy
Define the system, identify energy stores and describe transfers. Work done by a force transfers energy; total energy is conserved even when mechanical energy is not.
Use the mechanical model
E_k=rac12mv^2,\quad \Delta E_{p,g}=mg\Delta h,\quad E_{p,elastic}=rac12k(\Delta x)^2
Conserve their sum only when resistive transfers are absent or included explicitly.
Use rates and ratios
P=rac{\Delta E}{\Delta t}=Fv,\qquad \eta=rac{E_{useful}}{E_{input}}=rac{P_{useful}}{P_{input}}
Fuel energy density connects available input energy to a chosen volume.
Final checks
Check the system boundary, signs of work and potential-energy changes, the reference height, extension from natural length, and whether the quantity is energy, power, efficiency or energy density.