IB Physics HL C.5 Doppler Effect Question Bank
Practise IB Physics HL C.5 by solving Doppler-shift problems and interpreting moving-source, observer and wave-medium evidence.
- Syllabus
- First assessment 2025
- Course
- Physics HL
- Level
- HL
Practise IB Physics HL C.5 by solving Doppler-shift problems and interpreting moving-source, observer and wave-medium evidence.
Two loudspeakers, A and B, are driven in phase and with the same amplitude at a frequency of 850 Hz . Point P is located 22.5 m from A and 24.3 m from B. The speed of sound is 340 ms−1.

In another experiment, loudspeaker A is stationary and emits sound with a frequency of 850 Hz . The microphone is moving directly away from the loudspeaker with a constant speed v. The frequency of sound recorded by the microphone is 845 Hz .
Explain why the frequency recorded by the microphone is lower than the frequency emitted by the loudspeaker.
speed of sound relative to the microphone is less
wavelength unchanged «so frequency is lower»
OR
fewer waves recorded in unit time/per second «so frequency is lower»
Calculate v.
845=850×340340−vv=2.00<m s−1>−
A point source of sound is moving to the right at constant speed. The source emits sound waves of constant frequency. The speed of the source is less than the speed of sound. Which diagram correctly shows the wavefronts of the sound?




A
Star A is a main sequence star.
The data for Star A and the Sun are given in a table.

The peak wavelength of the radiation from Star A is measured by an observer on Earth. The observed wavelength is 0.007 % less than the value in (c)(i).
Outline how this difference arises.
Star A is moving toward Earth
Therefore the wavefronts are closer together «and the wavelength is reduced»
MP1 must be correct to earn MP2
For MP2 we need to see the connection to wavefronts.
Determine the speed, in kms−1, of Star A relative to Earth.
v=λΔλc=1000.007×3×108=2100021 km s−1
Allow ECF for MP2.
Do not award MP1 for use of the Doppler formulas for sound and mechanical waves.