IB Physics HL C 1 3 Shm Quantities Topic Practice

max velocity $=0.74( \pm 0.02) \mathrm{ms}^{-1}$;
recognize max velocity $=\omega x_{0}$;
$\omega=\left(\frac{2 \pi}{T}=\frac{2 \pi}{0.30}=\right) 20.9 \mathrm{rads}^{-1} ;$$x_{0}=\left(\frac{0.74}{20.9}=\right) 3.5( \pm 0.2) \times 10^{-2} \mathrm{~m} ;$
or
identifies displacement with area; uses one quarter of a cycle;
answer in the range of 30 to 40 mm ;
answer in the range of 33 to 37 mm ;