ConceptConceptDocsDocuments

IB Chemistry SL 2.2 Rate of Chemical Change Question Bank

Practise IB Chemistry SL 2.2 with questions on rate graphs, collision theory, activation energy, Maxwell–Boltzmann distributions and catalysts.

Syllabus
First assessment 2025
Course
Chemistry SL
Level
SL

2.2 Rate of chemical change question 1

[Maximum number: 7]

Iron rusts in the presence of oxygen and water. Rusting is a redox process involving several steps that produces hydrated iron(III) oxide, Fe2O3nH2O\mathrm{Fe}_{2} \mathrm{O}_{3} \bullet \mathrm{nH}_{2} \mathrm{O}, as the final product. The half-equations involved for the first step of rusting are given below.

Half-equation 1: Fe(s)Fe2+(aq)+2e\quad \mathrm{Fe}(\mathrm{s}) \rightarrow \mathrm{Fe}^{2+}(\mathrm{aq})+2 \mathrm{e}^{-}

Half-equation 2: O2(aq)+4e+2H2O(l)4OH(aq)\quad \mathrm{O}_{2}(\mathrm{aq})+4 \mathrm{e}^{-}+2 \mathrm{H}_{2} \mathrm{O}(\mathrm{l}) \rightarrow 4 \mathrm{OH}^{-}(\mathrm{aq})

Question (a)

(a)

Hydrogen peroxide decomposes according to the equation below.

2H2O2(aq)2H2O(l)+O2( g)2 \mathrm{H}_{2} \mathrm{O}_{2}(\mathrm{aq}) \rightarrow 2 \mathrm{H}_{2} \mathrm{O}(\mathrm{l})+\mathrm{O}_{2}(\mathrm{~g})

The rate of the decomposition can be monitored by measuring the volume of oxygen gas released. The graph shows the results obtained when a solution of hydrogen peroxide decomposed in the presence of a CuO catalyst.

Figure for Question (a) — IB Chemistry SL
[ 7 ]

Question (i)

(i)

The experiment is repeated with the same amount of a more effective catalyst, MnO2\mathrm{MnO}_{2}, under the same conditions and using the same concentration and volume of hydrogen peroxide. On the graph above, sketch the curve you would expect.

[ 1 ]

Question (ii)

(ii)

Outline how the initial rate of reaction can be found from the graph.

[ 2 ]

Question (iii)

(iii)

Outline a different experimental procedure that can be used to monitor the decomposition rate of hydrogen peroxide.

[ 1 ]

Question (iv)

(iv)

A Maxwell-Boltzmann energy distribution curve is drawn below. Label both axes and explain, by annotating the graph, how catalysts increase the rate of reaction.

Figure for Question (iv) — IB Chemistry SL
[ 3 ]

2.2 Rate of chemical change question 2

[Maximum number: 9]

Question (a)

(a)

A purple solution of potassium manganate( VII),KMnO4), \mathrm{KMnO}_{4}, reacts with ethanedioate ions according to the following equation.

2MnO4(aq)+5C2O42(aq)+16H+(aq)10CO2( g)+2Mn2+(aq)+8H2O(l)2 \mathrm{MnO}_{4}^{-}(\mathrm{aq})+5 \mathrm{C}_{2} \mathrm{O}_{4}^{2-}(\mathrm{aq})+16 \mathrm{H}^{+}(\mathrm{aq}) \rightarrow 10 \mathrm{CO}_{2}(\mathrm{~g})+2 \mathrm{Mn}^{2+}(\mathrm{aq})+8 \mathrm{H}_{2} \mathrm{O}(\mathrm{l})
[ 9 ]

Question (i)

(i)

Outline an experimental procedure which may be used to measure the rate of this reaction.

[ 3 ]

Question (ii)

(ii)

Sketch a graph to show the results of the experimental procedure outlined in (a) (i).

[ 2 ]

Question (iii)

(iii)

Outline how the rate of reaction at a particular time could be determined from the graph.

[ 1 ]

Question (iv)

(iv)

Discuss, in terms of collision theory, the effect of increasing temperature on the rate of this reaction.

[ 3 ]

2.2 Rate of chemical change question 3

[Maximum number: 3]

Question (a)

(a)

0.100 g of magnesium ribbon is added to 50.0 cm350.0 \mathrm{~cm}^{3} of 1.00moldm31.00 \mathrm{moldm}^{-3} sulfuric acid to produce hydrogen gas and magnesium sulfate.

Mg( s)+H2SO4(aq)H2( g)+MgSO4(aq)\mathrm{Mg}(\mathrm{~s})+\mathrm{H}_{2} \mathrm{SO}_{4}(\mathrm{aq}) \rightarrow \mathrm{H}_{2}(\mathrm{~g})+\mathrm{MgSO}_{4}(\mathrm{aq})
[ 3 ]

Question (i)

(i)

The graph shows the volume of hydrogen produced against time under these experimental conditions.

Figure for Question (i) — IB Chemistry SL

Sketch two curves, labelled I and II, to show how the volume of hydrogen produced (under the same temperature and pressure) changes with time when:

I. using the same mass of magnesium powder instead of a piece of magnesium ribbon;
II. 0.100 g of magnesium ribbon is added to 50 cm350 \mathrm{~cm}^{3} of 0.500moldm30.500 \mathrm{moldm}^{-3} sulfuric acid.

[ 2 ]

Question (ii)

(ii)

Outline why it is better to measure the volume of hydrogen produced against time rather than the loss of mass of reactants against time.

[ 1 ]
All question bank results loaded