IB Chemistry HL 3.3.3 Radical Substitution Question BankPractise IB Chemistry HL 3.3.3 Radical Substitution with focused questions on electron movement, radical steps and reaction products.SyllabusFirst assessment 2025CourseChemistry HLLevelHL
Exam pointswrite homolytic halogen initiation with UV light or heat and correctly marked radicalsbuild propagation steps that consume one radical and regenerate another chain carrierwrite termination by combining two radicals and explain the possible product mixture
3.3.3—Radical substitution question 1[Maximum number: 4]This question is about carbon and chlorine compounds.Question (a)(a)Ethane, C2H6\mathrm{C}_{2} \mathrm{H}_{6}C2H6, reacts with chlorine in sunlight. State the type of this reaction and the name of the mechanism by which it occurs.Type of reaction:Mechanism:[ 1 ]Show Answersubstitution AND «free-»radicalORsubstitution AND chainMarking guidance:Award [1] for "«free-»radical substitution" or "S R{ }_{R}R " written anywhere in the answer.Question (b)(b)Formulate equations for the two propagation steps and one termination step in the formation of chloroethane from ethane.Two propagation steps:One termination step:[ 3 ]Show AnswerTwo propagation steps:C2H6+∙Cl→C2H5∙+HCl\mathrm{C}_{2}\mathrm{H}_{6}+\bullet\mathrm{Cl} \rightarrow \mathrm{C}_{2}\mathrm{H}_{5}\bullet+\mathrm{HCl}C2H6+∙Cl→C2H5∙+HClC2H5∙+Cl2→C2H5Cl+∙Cl\mathrm{C}_{2}\mathrm{H}_{5}\bullet+\mathrm{Cl}_{2} \rightarrow \mathrm{C}_{2}\mathrm{H}_{5}\mathrm{Cl}+\bullet\mathrm{Cl}C2H5∙+Cl2→C2H5Cl+∙ClOne termination step, for example:C2H5∙+C2H5∙→C4H10\mathrm{C}_{2}\mathrm{H}_{5}\bullet+\mathrm{C}_{2}\mathrm{H}_{5}\bullet \rightarrow \mathrm{C}_{4}\mathrm{H}_{10}C2H5∙+C2H5∙→C4H10or:C2H5∙+∙Cl→C2H5Cl\mathrm{C}_{2}\mathrm{H}_{5}\bullet+\bullet\mathrm{Cl} \rightarrow \mathrm{C}_{2}\mathrm{H}_{5}\mathrm{Cl}C2H5∙+∙Cl→C2H5Clor:∙Cl+∙Cl→Cl2\bullet\mathrm{Cl}+\bullet\mathrm{Cl} \rightarrow \mathrm{Cl}_{2}∙Cl+∙Cl→Cl2Add to Test
Question (a)(a)Ethane, C2H6\mathrm{C}_{2} \mathrm{H}_{6}C2H6, reacts with chlorine in sunlight. State the type of this reaction and the name of the mechanism by which it occurs.Type of reaction:Mechanism:[ 1 ]Show Answersubstitution AND «free-»radicalORsubstitution AND chainMarking guidance:Award [1] for "«free-»radical substitution" or "S R{ }_{R}R " written anywhere in the answer.
Question (b)(b)Formulate equations for the two propagation steps and one termination step in the formation of chloroethane from ethane.Two propagation steps:One termination step:[ 3 ]Show AnswerTwo propagation steps:C2H6+∙Cl→C2H5∙+HCl\mathrm{C}_{2}\mathrm{H}_{6}+\bullet\mathrm{Cl} \rightarrow \mathrm{C}_{2}\mathrm{H}_{5}\bullet+\mathrm{HCl}C2H6+∙Cl→C2H5∙+HClC2H5∙+Cl2→C2H5Cl+∙Cl\mathrm{C}_{2}\mathrm{H}_{5}\bullet+\mathrm{Cl}_{2} \rightarrow \mathrm{C}_{2}\mathrm{H}_{5}\mathrm{Cl}+\bullet\mathrm{Cl}C2H5∙+Cl2→C2H5Cl+∙ClOne termination step, for example:C2H5∙+C2H5∙→C4H10\mathrm{C}_{2}\mathrm{H}_{5}\bullet+\mathrm{C}_{2}\mathrm{H}_{5}\bullet \rightarrow \mathrm{C}_{4}\mathrm{H}_{10}C2H5∙+C2H5∙→C4H10or:C2H5∙+∙Cl→C2H5Cl\mathrm{C}_{2}\mathrm{H}_{5}\bullet+\bullet\mathrm{Cl} \rightarrow \mathrm{C}_{2}\mathrm{H}_{5}\mathrm{Cl}C2H5∙+∙Cl→C2H5Clor:∙Cl+∙Cl→Cl2\bullet\mathrm{Cl}+\bullet\mathrm{Cl} \rightarrow \mathrm{Cl}_{2}∙Cl+∙Cl→Cl2